$p(x)= -x+4x^2+Cx^3-8x^4 \\ \\ \because \: given \: polynmial \: has \: zero \: at \: \\x = \frac{1}{4} \\ \\ \implies \: p\bigg(\frac{1}{4} \bigg) = 0...(1) \\ \\ plug \: x = \frac{1}{4} \: in \: p(x) \: we \: find \\ \\ p \bigg(\frac{1}{4} \bigg) = - \frac{1}{4} + 4 {\bigg(\frac{1}{4} \bigg)}^{2} + c {\bigg(\frac{1}{4} \bigg)}^{3} - 8 {\bigg(\frac{1}{4} \bigg)}^{4} \\ \\ 0 = - \frac{1}{4} + \cancel 4 \times {\frac{1}{\cancel{16} } } + c {\bigg(\frac{1}{64} \bigg)} - \cancel 8 \times \frac{1}{\cancel{256} } \\ \\0 =\cancel{ - \frac{1}{4}} + \cancel {{\frac{1}{4} }} + c {\bigg(\frac{1}{64} \bigg)} - \times \frac{1}{32} \\ \\0 = c {\bigg(\frac{1}{64} \bigg)} - \frac{1}{32} \\ \\c {\bigg(\frac{1}{64} \bigg)} = \frac{1}{32} \\ \\ c = \frac{1}{32} \times 64 \\ \\ c = 2$

5 0

3 years ago

jekas [21]

Answer:

b= -8

Step-by-step explanation:

we have: 3y +12 = 6x <=> y + 4 = 2x <=> y= 2x - 4

=> 2y=4x + b

<=> 2(2x-4) = 4x +b

<=> 4x - 8= 4x +b

<=> b = -8

6 0

3 years ago

Read 2 more answers

Does x = 5 satisfy the equation 3 (x +1) = 3x + 3

Yuki888 [10]

Answer:

yes

Step-by-step explanation:

To know if x = 5 satisfy the equation or not, you just have to applied it into your equation:

3 (5+1) = 3 * 5 + 3

18 = 18

So x = 5 do satisfy the equation

Hope this help you :3

4 0

3 years ago

In the past ten years, the population of a city decreased from 90,000 to 75,000 Find the percent decrease.

vfiekz [6]

The answer is 31.5%.

8 0

3 years ago