Alice has 36 possibilities of choosing ,Bob 126 and Kevin 84.
Alice, Bob and Kevin
7 different Flavors:
Chocolate
Vanillla
mint chip
strawberry
cookie dough
banana
caramel
The order of the 9 scoops does not matter.
_ _ _ _
a) How many ways can she choose her 9 scoops so she gets at least 1 scoop of each flavor?
Since there are 7 flavors, and she wants at least one of each then we have:
Alice has 36 possibilites of choosing
b) Bob
Since Bob can't eat too much he can't do no more than 4
Bob has 126 possibilities of making his choice.
c) Kevin
3 scoups of banana or 3 scoups of strawberries.
Considering He wants 9 scoups.
Kevin has 84 possibilities for banana or strawberries
1) m=-2
2) C) y=-3/4x -6
3) D) y=2/5x-2
I don't understand 4 nor 5. My apologies.
6) Parallel
Answer:
y= -1/4x+2
Step-by-step explanation:
i think this might be right.
Answer:
d = 7
Step-by-step explanation:
7 times 5 = 35
or
35/5 = 7
Answer:
282240 ways
Step-by-step explanation:
number of items = 9 different items
Ranking based on worth
<u>determine number of ways to arrange the 9 items such that the 2 most expensive are apart</u>
first step: consider the 2expensive items as 1
∴ number of permutation = [ ( 9 - 2 ) + 1 ]! * 2!
= [ 8 ] ! * 2! = 80640
Total number of permutation/arrangement = 9! = 362880
hence to arrange the 9 items without having the two most expensive items together
= 362,880 - 80640
= 282240 ways
