Question

Place the numbers 0 to 8, inclusive, in the magic square so that the sum of the numbers in each row, column, and diagonal is the same number, 12.

Answer 1

Answer: See attached table

Step-by-step explanation:

$\begin{table}[]\begin{tabular}{lllll} & & & & \\ & & & & \\ & & & & \\ & & & & \end{tabular}\end{table}$+---+---+---+

| 1 | 8 | 2 |

+---+---+---+

| 6 | 4 | 2 |

+---+---+---+

| 5 | 0 | 7 |

+---+---+---+

Proofs:
First row: 1+6+5 = 12

Second row: 8+4+0 = 12

Third row: 2+2+7 = 12

First column: 1+8+2 = 12

Second column: 6+4+2 = 12

Third column: 5+0+7 = 12

Diagonal starting from top left to bottom right: 1+4+7 = 12

Diagonal staring from top right to bottom left: 2+4+5 = 12