It's simple, you just have to times everything. 5000 x 3.2% x 5 years. After calculating these, 3.2 is as 0.032 so there would be three decimal places. So then it will e 5000 x 0.032 x 5
we can see that
Z , L and S are three points of line ZS
so, Z , L and S are collinear
and
Z , L and S lie on plane M
so, they are coplanar
so, option-C....................Answer
It is 5 units
because -9,3 is up and -9,-2 is down
5
Answer: The probability of selecting at least one boy (the probability that the 2 students selected are not both girls) is 62/95 or 0.6526
Step-by-step explanation:
From the question, the students to be chosen must be selected from a group of eight boys and twelve girls. This means that the total number of students that these two students must be chosen from is:
8 + 12 = 20 students.
The next step would be to find the probability of selecting a boy:
= Total number of boys/Total number of students
= 8/20
We will also find the probability of selecting one girl from the group
= Total number of girls/Total number of students
= 12/20
To find the probability that the two selected students are not girls is the same as finding the probability of selecting at least one boy. To do this, we will first find the probability of choosing all girls and then subtract it from 1.
The probability of selecting or choosing 2 girls (without replacement)
(12/20) × (11/19)
= 132/380
= 33/95
Then, the probability of selecting at least one boy (the probability that the students chosen are not both girls)
= 1 - (33/95)
= (95/95) - (33/95)
= 62/95 or 0.6526
Answer:
x¹³ - x⁹ - 9x⁸ + 9x⁴
Explanation:
Before we begin, remember the following:
xᵃ * xᵇ = xᵃ⁺ᵇ
Now, for the given:
To answer the question, we will simply multiply each term from the first bracket by each term from the second bracket and then combine like terms to get the final expression.
This can be done as follows:
(x⁸ - x⁴)(x⁵ - 9)
x⁸(x⁵) + x⁸(-9) - x⁴(x⁵) - x⁴(-9)
x¹³ - 9x⁸ - x⁹ + 9x⁴
Rearrange in order of decreasing powers, we will end up with:
x¹³ - x⁹ - 9x⁸ + 9x⁴
Hope this helps :)
