They would need 34.125 tons of rations.
In order to find this, we first need to see how many pounds of rations a single soldier eats in a week. To do this, we take the total eaten in 3 weeks and divide by 3. Then we divide by the number of soldiers.
16,380/3 weeks= 5460 lbs per week
5460/520 soldiers = 10.5 lbs per soldier per week
Now we look to see how many soldiers we will have in total after adding. There are 520 to start and we add 780 to get 1300 total. Next we multiply that by the total per soldier per week.
10.5lbs per soldier per week * 1300 soldiers = 13,650lbs per week
Then we have to multiply by the 5 weeks that battalion will be there.
13,650lbs * 5 weeks = 68,250lbs of rations or 24.125 tons.
Answer:
18.84 estimated, 6π exactly
Step-by-step explanation:
Hi!
<u>The formula for finding the circumference of a circle is 2πr:</u>
In that case, all we need to do <em>first </em>is to divide the diameter by 2, so we can substitute that into the equation.
6 ÷ 2 = 3
So we have 2π × 3 to solve.
2π × 3 = 6π
We can estimate the circumference by multiplying by 3.14.
6 × 3.14 = 18.84
(actually multiplying by π gives 18.849... which is pretty close!)
Thus, the circumference is
.
Hope this helps!
Answer:
7.3% of the bearings produced will not be acceptable
Step-by-step explanation:
Problems of normally distributed samples can be solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

Target value of .500 in. A bearing is acceptable if its diameter is within .004 in. of this target value.
So bearing larger than 0.504 in or smaller than 0.496 in are not acceptable.
Larger than 0.504
1 subtracted by the pvalue of Z when X = 0.504.



has a pvalue of 0.9938
1 - 0.9938= 0.0062
Smaller than 0.496
pvalue of Z when X = -1.5



has a pvalue of 0.0668
0.0668 + 0.0062 = 0.073
7.3% of the bearings produced will not be acceptable
Answer:
1/16
Step-by-step explanation:
multiply the separate probabilities. On the number, it's 1/8 chance you'll get 1. On the letter, it's a 3/6 or 1/2 chance you'll get an A.
1/8 * 1/2 is 1/16.