<h3>Answer:</h3>
room 3 or 4
<h3>Explanation:</h3>
We assume the inequalities tell the rooms that were checked and found empty.
The solution to 3) is ...
... 2x + 3 > 11
... 2x > 8 . . . . . subtract 3
... x > 4 . . . . . . .divide by 2
The solution to 4) is ...
... -3x > -9
... x < 3 . . . . . . divide by -3
Thus, rooms greater than 4 and less than 3 were found empty. Rooms 3 and 4 were not checked, so either one could hold Nessie.
_____
The other inequalities have solutions that are already covered by the solutions to these.
1) x < -1 . . . . after subtacting 4
2) x > 5 . . . . after multiplying by 5
Answer:
Step-by-step explanation:
11) First write in decreasing exponential terms and fill in blanks with zeros.
Our goal is to eliminate all term in the dividend by subtraction
________________
2v - 2 | 2v³ - 16v² + 0v + 13
we see that 2v needs to be multiplied by 1v² to eliminate the first term
<u> v² </u>
2v - 2 | 2v³ - 16v² + 0v + 13
<u>- (2v³ - 2v²)</u>
0 - 14v²
multiply your estimate by your divisor and subtract from the dividend.
bring down the next term and repeat.
<u> v² -7v </u>
2v - 2 | 2v³ - 16v² + 0v + 13
<u>- (2v³ - 2v²)</u>
0 - 14v² + 0v
<u>-(-14v² + 14v)</u>
- 14v
repeat again
<u />
<u> v² - 7v - 7 </u>
2v - 2 | 2v³ - 16v² + 0v + 13
<u>- (2v³ - 2v²)</u>
0 - 14v² + 0v
<u>-(-14v² + 14v)</u>
- 14v + 13
<u>-(-14v + 14)</u>
-1
and remainder gets put over the divisor and appended
v² - 7v - 7 - 1/(2v - 2)
13) Same process
<u> </u>
5a + 1 | 40a³ - 12a² - 39a - 5
<u> 8a² </u>
5a + 1 | 40a³ - 12a² - 39a - 5
<u>-(40a³ + 8a²)</u>
-20a² - 39a
<u> 8a² - 4a </u>
5a + 1 | 40a³ - 12a² - 39a - 5
<u>-(40a³ + 8a²)</u>
-20a² - 39a
-(-<u>20a² - 4a)</u>
-35a - 5
<u> 8a² - 4a - 7 </u>
5a + 1 | 40a³ - 12a² - 39a - 5
<u>-(40a³ + 8a²)</u>
-20a² - 39a
-(<u>20a² - 4a)</u>
-35a - 5
-<u>(-35a - 7)</u>
2
8a² - 4a - 7 + 2/(5a + 1)
You don't need to use info for p(C)
Answer:
6.24 is the answer rounded to the nearest hundreth
