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elixir [45]
3 years ago
7

Half a number plus 5 is 11.What is the number?​

Mathematics
2 answers:
SOVA2 [1]3 years ago
6 0
<h3>Solution :</h3>

<u>Let x be the number</u>

\small\bold\red{→}\small\bold{(\frac{1}{2} )x + 5 = 11}

\small\bold\red{→}\small\bold{(\frac{1}{2})x + 5 - 5 = 11 - 5}

\small\bold\red{→}\small\bold{(\frac{1}{2})x = 6}

\small\bold\red{→}\small\bold{2 × (\frac{1}{2})x = 6 × 2 }

\small\bold\red{→}\small\bold{x = 12}

Ber [7]3 years ago
5 0

Hello.

First, "half a number" means we divide that number by 2.

Let's say the number is z.

Divide z by 2:

\displaystyle\frac{z}{2}

Add 5 to it:

\displaystyle\frac{z}{2} +5

Now, this expression equals 11:

\displaystyle\frac{z}{2} +5=11

Subtract 5 from both sides:

\displaystyle\frac{z}{2} =11-5

\displaystyle\frac{z}{2} =6

Now, in order to get rid of the fraction, we should multiply the entire equation by 2:

\displaystyle\frac{z}{2} *2=6*2

z=6*2

\Large\boxed{z=12}

I hope it helps.

Have an outstanding day. :)

\boxed{imperturbability}

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You can solve this since you can develop 3 equations for your 3 unknowns. Each equation is made using the Pythagorean theorem:

1) x^2 = y^2 + 16^2
2) z^2 = y^2 + 4^2
3) (16 + 4)^2 = z^2 + x^2

Simplifying the above we get:

1) x^2 = y^2 + 256
2) z^2 = y^2 + 16
3) 400 = z^2 + x^2

We want to solve for z. There are several ways but an easy one is with substitution. Start by rearranging 2) and 3) like this:

2’) y^2 = z^2 - 16
3’) x^2 = 400 - z^2

Now we have expressed x and y in terms of z. Plug these values into the unused equation, 1), to solve for z:

1’) 400 - z^2 = z^2 - 16 + 256
2z^2 = 160
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Step-by-step explanation:

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AlladinOne [14]

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x ^ 2 + 3x-5 = 0

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Substituting the values:

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