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gulaghasi [49]
2 years ago
14

For a given show, a theater charges $80 for a premium ticket and $30 for a regular ticket. If a total of n tickets were sold and

p of them were premium tickets, what is the total amount, in dollars, from the sale of regular tickets and premium tickets?
Please explain the process.
Mathematics
1 answer:
netineya [11]2 years ago
8 0

Answer:

50p + 30n

Step-by-step explanation:

Cost of each premium ticket = $80.

Cost of each regular ticket = $30

Total tickets sold = n

We are told that p tickets were sold. Thus;

Total tickets sold is; p + (n - p)

Thus total amount generated is;

T = 80p + 30(n - p)

T = 50p + 30n

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Answer: D) f(n)=8(1.5)^{n-1}


Step-by-step explanation:

From the given table we can see that this is not representing a linear function as the rate of change is not constant.

So it can be exponential growth function A(b)^{n-1},  where A is the initial amount , b is the multiplicative rate of growth and n is the time period in weeks.

Now here at n=1 , f(n)=8

Therefore, A=8

Now, for n=2

f(2)=8(b)^{2-1}\\\Rightarrow12=8b\\\Rightarrow\ b=\frac{12}{8}\\\Rightarrow\ b=1.5

By substitute the values of A and b in the above equation, we get the equation f(n)=8(1.5)^{n-1}

Therefore, the function best shows the relationship between n and f(n) is

f(n)=8(1.5)^{n-1}, where n is the number of weeks.

7 0
2 years ago
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Convince me why points B&C are solutions to this system of linear inequalities.
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The coordinates of B and C are solutions to the system of inequalities because both are true to the two inequalities. A is not a solution to the system of inequalities because it is only true to “y is less than or equal to 2x”.
3 0
2 years ago
I toss an unfair coin 12 times. This coin is 65% likely to show up heads. Calculate the probability of the following.
mars1129 [50]

Answer:

a. 0.0368

b. 0.99992131

c. 0.2039

d. 0.0048

e. 0.6533

Step-by-step explanation:

Let the probability of obtaining a head be p = 65% = 13/20 = 0.65. The probability of not obtaining a head is q = 1 - p = 1 -13/20 = 7/20 = 0.35

Since this is a binomial probability, we use a binomial probability.

a. The probability of obtaining 11 heads is ¹²C₁₁p¹¹q¹ = 12 × (0.65)¹¹(0.35) = 0.0368

b. Probability of 2 or more heads P(x ≥ 2) is

P(x ≥ 2) = 1 - P(x ≤ 1)

Now P(x ≤ 1) = P(0) + P(1)

= ¹²C₀p⁰q¹² + ¹²C₁p¹q¹¹

= (0.65)⁰(0.35)¹² + 12(0.65)¹(0.35)¹¹

= 0.000003379 + 0.00007531

= 0.0007869

P(x ≥ 2) = 1 - P(x ≤ 1)

= 1 - 0.00007869

= 0.99992131

c. The probability of obtaining 7 heads is ¹²C₇p⁷q⁵ = 792(0.65)⁷(0.35)⁵ = 0.2039

d. The probability of obtaining 7 heads is ¹²C₉q⁹p³ = 220(0.65)³(0.35)⁹ = 0.0048

e. Probability of 8 heads or less P(x ≤ 8) = ¹²C₀p⁰q¹² + ¹²C₁p¹q¹¹ + ¹²C₂p²q¹⁰ + ¹²C₃p³q⁹ + ¹²C₄p⁴q⁸ + ¹²C₅p⁵q⁷ + ¹²C₆p⁶q⁶ + ¹²C₇p⁷q⁵ + ¹²C₈p⁸q⁴

= = ¹²C₀(0.65)⁰(0.35)¹² + ¹²C₁(0.65)¹(0.35)¹¹ + ¹²C₂(0.65)²(0.35)¹⁰ + ¹²C₃(0.65)³(0.35)⁹ + ¹²C₄(0.65)⁴(0.35)⁸ + ¹²C₅(0.65)⁵(0.35)⁷ + ¹²C₆(0.65)⁶(0.35)⁶ + ¹²C₇(0.65)⁷(0.35)⁵ + ¹²C₈(0.65)⁸(0.35)⁴

= 0.000003379 + 0.00007531 + 0.0007692 + 0.004762 + 0.01990 + 0.05912 + 0.1281 + 0.2039 + 0.2367

= 0.6533

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The probabilty of getting an A in math is 0.65 and the probability of getting an a in science is 0.62 whats the probability of g
ruslelena [56]

Answer:

The probability of getting an a in both courses is 1.27

Step-by-step explanation:

Probability of getting A in Math, P(M) = 0.6 5

Probability of getting A in Science, P(S) = 0.62

Required probability of getting A in both courses, P(M and S)

= P(M) + P(S)

= 0.65 + 0.62

= 1.27

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3 years ago
A box of cookies contains 4 chocolate and 6 butter cookies. Miguel randomly selects a cookie and eats it. Then he randomly selec
laila [671]

Answer:

The probability of the flavor of the second cookie is always going to be dependent on the first one eaten.

Step-by-step explanation:

Since the number of the type of cookies left depends on the first cookie taken out.

This is better explained with an example:

  1. Probability Miguel eats a chocolate cookie is 4/10. The probability he eats a chocolate or butter cookie after that is <u>3/9</u> and <u>6/9</u> respectively. This is because there are now only 3 chocolate cookies left and still 6 butter cookies left.
  2. In another case, Miguel gets a butter cookie on the first try with the probability of 6/10. The cookies left are now 4 chocolate and 5 butter cookies. The probability of the next cookie being chocolate or butter is now <u>4/9</u> and <u>5/9</u> respectively.

The two scenarios give us different probabilities for the second cookie. This means that the probability of the second cookie depends on the first cookie eaten.

7 0
2 years ago
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