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SIZIF [17.4K]
3 years ago
5

If square HIJK is dilated by a scale factor of

Mathematics
2 answers:
WITCHER [35]3 years ago
3 0
C. point K is (3,-3) and the dilation moves from 3 to 1 so you divide both X and Y coordinates by 3 to get (1,-1)
hope this helps.

Sav [38]3 years ago
3 0

Answer:

C) (1, -1)  

Step-by-step explanation:

When a figure is dilated, the coordinates of each point are multiplied by the scale factor.  The scale factor in this problem is 1/3; this means that every point gets multiplied by 1/3.

The coordinates of K are (3, -3).  Applying the dilation, we have

1/3(3, -3) = (1/3*3, 1/3*-3) = (1, -1)

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Step-by-step explanation:

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IN THE FIGURE BC IS PARALLEL TO AD. AREA OF TRIANGLE ABC IS 100 cm². WHAT IS THE AREA OF TRIANGLE BCD
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Step-by-step explanation:

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2 years ago
In a study of the effect of college student employment on academic performance, the following summary statistics for GPA were re
11Alexandr11 [23.1K]

Answer:

Step-by-step explanation:

This is a test of 2 independent groups. The population standard deviations are not known. Let μemployed(μ1) be the sample mean of students who are employed and μnot employed(μ2) be the sample mean of students who are not employed

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H0 : μ1 = μ2 H0 : μ1 - μ2 = 0

The alternative hypothesis is

H1 : μ1 < μ2 H1 : μ1 - μ2 < 0

Since sample standard deviation is known, we would determine the test statistic by using the t test. The formula is

(μ1 - μ2)/√(s1²/n1 + s2²/n2)

From the information given,

μ1 = 3.22

μ2 = 3.33

s1 = 0.475

s2 = 0.524

n1 = 172

n2 = 116

t = (3.22 - 3.33)/√(0.475²/172 + 0.524²/116)

t = - 1.81

The formula for determining the degree of freedom is

df = [s1²/n1 + s2²/n2]²/(1/n1 - 1)(s1²/n1)² + (1/n2 - 1)(s2²/n2)²

df = [0.475²/172 + 0.524²/116]²/[(1/172 - 1)(0.475²/172)² + (1/116 - 1)(0.524²/116)²] = 0.00001353363/0.00000005878

df = 230

We would determine the probability value from the t test calculator. It becomes

p value = 0.036

Since alpha, 0.05 > than the p value, 0.036, then we would reject the null hypothesis.

Therefore, at a 5% significant level, this information support the hypothesis that for students at this university, those who are not employed have a higher mean GPA than those who are employed

3 0
3 years ago
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Answer:

<h3>C. They are both perfect squares and perfect cubes.</h3>

Step-by-step explanation:

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Given the following patterns;

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Also 1 is perfect cube since 1*1*1 = 1³ = 1 (cube of the value gives 1)

Similarly for the expression;

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Also 4*4*4 = 64

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This values are easily expressed as a constant multiple of a number showing that they are both perfect squares and perfect cubes.

4 0
3 years ago
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