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Paha777 [63]
3 years ago
11

2×2= Have a nice night.

Mathematics
1 answer:
nydimaria [60]3 years ago
3 0

Answer:

4

Step-by-step explanation:

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How to find if a triangle is acute, right, or obtuse with the sides?
masya89 [10]

Hey!

Hope this helps...

~~~~~~~~~~~~~~~~~~~~~~~~~~~

This is actually pretty simple...

[attachment below will help too]


An obtuse triangle is where one angles is greater than 90*

A right triangle is where one angle is exactly equal to 90*

An acute triangle is where one angle is less than 90*


The BEST WAY to tell the difference between these triangles is to see/find either a 1/4 square (found on right triangles) or 1/3 circles (found on acute and obtuse triangles)...

6 0
3 years ago
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It says to do 81^3/4 and i don’t know how to simplify that
scoundrel [369]

\bf 81^{\frac{3}{4}}~~ \begin{cases} 81=&3\cdot 3\cdot 3\cdot 3\\ &3^4 \end{cases}\qquad \implies (3^4)^{\frac{3}{4}}\implies 3^{4\cdot \frac{3}{4}}\implies 3^1\implies 3

7 0
3 years ago
Find a formula for the inverse of the function. f(x) = e^6x − 9
STatiana [176]

Answer:

f^{-1}(x)=\frac{1}{6}\ln(x+9)

Step-by-step explanation:

So we have the function:

f(x)=e^{6x}-9

To solve for the inverse of a function, change f(x) and x, change the f(x) to f⁻¹(x), and solve for it. Therefore:

x=e^{6f^{-1}(x)}-9

Add 9 to both sides:

x+9=e^{6f^{-1}(x)}

Take the natural log of both sides:

\ln(x+9)=\ln(e^{6f^{-1}(x)})

The right side cancels:

\ln(x+9)=6f^{-1}(x)

Divide both sides by 6:

f^{-1}(x)=\frac{1}{6}\ln(x+9)

And we're done!

7 0
3 years ago
What does x equal to x/7 - 4 = -5
beks73 [17]

Answer:

x = -7

Step-by-step explanation:

So we are asked to find what x is equal to in the equation:

\frac{x}{7}-4=-5

In other words, we are asked to solve for x.

\frac{x}{7}-4=-5

Add 4 to both sides of the equation.

\frac{x}{7}=-1

Multiply both sides by 7.

x = -7

So we have solve the equation for x and have found that x = -7.

I hope you find my answer and explanation to be helpful. Happy studying.

7 0
3 years ago
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A relation is (1 point)
Karo-lina-s [1.5K]

Answer:

The range of a relation is the output (y) values of the relation. The range represents the set of the y-coordinates from the ordered pairs.

Step-by-step explanation:

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