A baseball has a 48 cm diameter. What is the volume of the contents of the ball?
1 answer:
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First, you have to find the moment of inertia along the x and y axes. Constant density is denoted as k.
Then, the radii of gyration for
x = √[I_x/m]
y = [I_y/m]
where m = k(15-4)² = 121k. Then,
x = y = [4880.33k/121k] = 40.33
I hope I was able to help you. Have a good day.
Then, the radii of gyration for
x = √[I_x/m]
y = [I_y/m]
where m = k(15-4)² = 121k. Then,
x = y = [4880.33k/121k] = 40.33
I hope I was able to help you. Have a good day.
Answer:
80
Step-by-step explanation:
Think of it as a Venn diagram. One circle is the people who like dogs, and one circle is the people who like cats. The overlap is people who like both dogs and cats.
190 people in the survey said they like dogs. That includes the people who like both dogs and cats.
141 people in the survey said they like cats. That includes the people who like both dogs and cats.
If we simply add the two numbers together, we'll be counting the overlap twice. So to find the total number of people who like dogs or cats, we have to subtract one overlap.
dogs or cats = 190 + 141 − x
Therefore:
190 + 141 − x + 88 = 339
419 − x = 339
x = 80
80 people said they liked both cats and dogs.
Complete question:
He amount of time that a customer spends waiting at an airport check-in counter is a random variable with mean 8.3 minutes and standard deviation 1.4 minutes. Suppose that a random sample of n equals 47 customers is observed. Find the probability that the average time waiting in line for these customers is
a) less than 8 minutes
b) between 8 and 9 minutes
c) less than 7.5 minutes
Answer:
a) 0.0708
b) 0.9291
c) 0.0000
Step-by-step explanation:
Given:
n = 47
u = 8.3 mins
s.d = 1.4 mins
a) Less than 8 minutes:
P(X' < 8) = P(Z< - 1.47)
Using the normal distribution table:
NORMSDIST(-1.47)
= 0.0708
b) between 8 and 9 minutes:
P(8< X' <9) =
= P(-1.47 <Z< 6.366)
= P( Z< 6.366) - P(Z< -1.47)
Using normal distribution table,
0.9999 - 0.0708
= 0.9291
c) Less than 7.5 minutes:
P(X'<7.5) =
P(X' < 7.5) = P(Z< -3.92)
NORMSDIST (-3.92)
= 0.0000