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Mekhanik [1.2K]
3 years ago
11

Average movie prices in the United States​ are, in​ general, lower than in other countries. It would cost ​$80.09 to buy three t

ickets in Japan plus two tickets in Switzerland. Three tickets in Switzerland plus two tickets in Japan would cost ​$75.81. How much does an average movie ticket cost in each of these​ countries?
Mathematics
1 answer:
egoroff_w [7]3 years ago
8 0

Answer:x=17.67 y=13.15

Step-by-step explanation: really hoping it is right!

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- 40 = -5r (algebra)
Gekata [30.6K]

Answer:

r=8

hope this helps

have a good day :)

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
How do i graph x-y=-3
solmaris [256]
X - y = -3
y = x + 3.......slope = 1, y intercept = (0,3)

to find x int, sub in 0 for y and solve for x
x - y = -3
x - 0 = -3
x = -3....so the x intercept = (-3,0)

plot ur points (0,3) and (-3,0)......now start at (-3,0)....and since ur slope is 1, go up one, and to the right 1, and up 1, and to the right 1.....do this over as many times as needed and u should cross the y axis at (0,3)
6 0
4 years ago
Read 2 more answers
What is the slope of a line that is perpendicular to line Y = 1 ?
Alekssandra [29.7K]
Undefined

Rise/ run = slope

1 rise / 0 run = 1/0 which is undefined
8 0
3 years ago
What is the slope of the line that passes through the points (4,10) and (1,10) in simplest form​
GuDViN [60]

Answer:

0

Step-by-step explanation:

We can find the slope by using

m = (y2-y1)/(x2-x1)

   = (10-10)/(1-4)

   = 0/-3

  =0

7 0
4 years ago
the initial vertical velocity of a rocket shot straight up is 42 meters per second. How long does it take for the rocket to retu
Snowcat [4.5K]
It takes 4.3 seconds for the rocket to return to earth.

The equation is:
0=-9.8t^2+v_0t+h_0
where -9.8m/sec² is the acceleration due to gravity, v₀ is the initial velocity, and h₀ is the initial height.  We will go from the assumption that the rocket is launched from the ground, so h₀=0, and we are told that the initial velocity, v₀, is 42.  This gives us:

0=-9.8t^2+42t

We will use the quadratic formula to solve this.  The quadratic formula is:
x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

Plugging in our information we have:
t=\frac{-42\pm \sqrt{42^2-4(-9.8)(0)}}{2(-9.8)}
\\
\\=\frac{-42\pm \sqrt{1764-0}}{-19.6}
\\
\\=\frac{-42\pm \sqrt{1764}}{-19.6}
\\
\\=\frac{-42\pm 42}{-19.6}=\frac{-42-42}{-19.6} \text{ or } \frac{-42+42}{-19.6}
\\
\\=\frac{-84}{-19.6}\text{ or }\frac{0}{-19.6}
\\
\\=4.3\text{ or }0

x=0 is when the rocket is launched; x=4.3 is when the rocket lands.
8 0
4 years ago
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