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ale4655 [162]
3 years ago
6

Please help to find the HCF and LCM of this question ​

Mathematics
1 answer:
poizon [28]3 years ago
4 0

Step-by-step explanation:

Explanation is in the attachment

<em>H</em><em>ope </em><em>it</em><em> is</em><em> helpful</em><em> to</em><em> you</em>

<em> </em><em> </em><em>✌️</em><em>✌️</em><em>✌️</em><em>✌️</em><em>✌️</em><em>✌️</em><em>✌️</em>

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Roger owns a one acre piece of land . The length of the land is 484 feet. What is the width of his property
JulsSmile [24]

1 acre = 43560 square feet

43560 = 484 * X

X=43560/484 = 90

the width = 90 feet

4 0
3 years ago
Mrs. Parson cuts 1 /3 of a piece of construction paper. She uses 1 / 6 of the piece to make a flower. What fraction of the sheet
Assoli18 [71]

Answer:

1/3*1/6 is ur answer.

1/18

4 0
2 years ago
(9a^2 + 7a + 8) - (2a^2 + 5a + 1)
Sergio [31]

Answer:  7a^2+2a+7

Step-by-step explanation:Distribute the Negative Sign:

=9a2+7a+8+−1(2a2+5a+1)

=9a2+7a+8+−1(2a2)+−1(5a)+(−1)(1)

=9a2+7a+8+−2a2+−5a+−1

Combine Like Terms:

=9a2+7a+8+−2a2+−5a+−1

=(9a2+−2a2)+(7a+−5a)+(8+−1)

=7a2+2a+7

8 0
2 years ago
A large but sparsely populated county has two small hospitals, one at the south end of the county and one at the north end. The
Readme [11.4K]

Answer:

Step-by-step explanation:

Probability distribution of this type is a vicariate distribution because it specifies two random variable X and Y. We represent the probability X takes x and Y takes y by

f(x,y) = P((X=x,Y=y) ,

and given that the random variables are independent the joint pmf isbgiven by:

f(x,y) = fX(x) .fY(y) and this gives the table (see attachment)

(b) the required probability is given by considering X=0,1 and Y =0,1

f(x,y) = sum{(P(X ≤ 1, Y ≤ 1) }

= [0.1 +0.2 ] × [0.1 + 0.3]

= 0.3 × 0.4

= 0.12

Now we find

fX(x) = sum{[f(x.y)]} for y =0, 1 and similarly for fY(y)= sum{[f(x,y)]} for x=0, 1

fX(x) = sum{[f(x,y)]}= 0.1+0.3

= 0.4

fY(y) = sum{[f(x.y)]} = 0.1 + 0.2

= 0.3

Since fY(y) × fX(x) = 0.4 × 0.3

= 0.12

Hence f(x,y) = fX(x) .fY(y), the events are independent

(c) the required event is give by: [P(X<=1, PY<=1)]

= P(X<=1) . P(Y<=1)

= [sum{[f(x.y]} over Y=0,1] × [sum{[f(x.y)]}, over X= 0, 1

= 0.4 × 0.3

= 0.12

(d) the required event is given by the idea that: either The South has no bed and the North has or the the North has no bed and the South has. Let this event be A

A =sum[(P(X = 1<= x<= 4, Y =0)] + sum[P(X =0 Y= 1 <= x <= 3)]

A = [0.02 + 0.03 + 0.02 + 0.02] + [0.03 + 0.04 + 0.02]

A = [0.09] + [ 0.09]

A = 0.18

Pls note the sum of the vertical column X=2 is 0.3

3 0
3 years ago
Heyyyyyy , Can you please help me with this
erik [133]

Answer:

19 houses

Step-by-step explanation:

90*(2/5)=36

90-36=54

54*(2/3)=37

54-37=19

8 0
2 years ago
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