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3 years ago

Help me plss i have to turn this in ASAP

Mathematics

1 answer:

Stells [14]3 years ago

5 0

Answer:

1. 9/25

3. 27 cm ^3

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Instructions: Find the value of the trigonometric ratio. Make sure to simplify the fraction if

g100num [7]

Step-by-step explanation:

$\sin(x) = \frac{12}{13}$

3 0

3 years ago

A square has a diagonal length of 10 ft. Draw a diagram and determine the perimeter of the square.

denpristay [2]

The perimeter of the square is: $20\sqrt2$ ft

Step-by-step explanation:

The picture is attached with the answer.

the diagonal of a square divides it into two right angled-triangles.

We can use one of the triangle to find the length of side as the diagonal will be the hypotenuse of the triangle

Let a be the side of the square, then according to Pythagoras theorem

$d^2=a^2+a^2\\(10)^2 = 2a^2\\2a^2=100$

Dividing both sides by 2

$\frac{2a^2}{2}=\frac{100}{2}\\a^2=50$

Taking Square root on both sides

$\sqrt{a^2}=\sqrt{50}\\a=\sqrt{25*2}\\a=\sqrt{5^2 * 2}\\a=5\sqrt{2}\ ft$

Now,

$P = 4a\\P = 4 * 5\sqrt{2}\\=20\sqrt{2}\ ft$

Hence,

The perimeter of the square is: $20\sqrt2$ ft

Keywords: Perimeter, Pythagoras Theorem

Learn more about Square at:

#learnwithBrainly

5 0

4 years ago

The scale on a map is 1 :50000.

mestny [16]

Answer:

The actual area of the field in square kilometers is $30000000 km^2$

Step-by-step explanation:

Scale : 1 cm = 50000 km

Area of field on map = $1.2 cm^2$

Now , 1 cm = 5000 km

$1 cm^2 = (5000 km)^2$

We are supposed to find the actual area of the field in square kilometers.

So, the actual area of the field in sq. km = $1.2 \times (5000)^2$

Actual area of the field in sq. km $=30000000 km^2$

Hence the actual area of the field in square kilometers is $30000000 km^2$

6 0

3 years ago

The downtime per day for a computing facility has mean 4 hours and standard deviation .8 hour. Suppose that we want to compute p

xz_007 [3.2K]

Answer:

Step-by-step explanation:

Given :

Mean, μ = 4

Standard deviation, s = 0.8

Sample size, n = 30

The distribution is independent.

Z = (x - μ) / s /sqrt(n)

Probability that downtime period is between 1 and 5

P(1≤ x ≤ 5) :

[(x - μ) / (s /sqrt(n))] ≤ Z ≤ [(x - μ) / (s /sqrt(n))]

[(1 - 4) / (0.8 /sqrt(30))] ≤ Z ≤ [(5 - 4) / (0.8 /sqrt(30)]

[-3 / 0.1460593] ≤ Z ≤] 1 / 0.1460593]

P(-20.539602 ≤ Z ≤ 6.8465342)

P(Z ≤ 6.8465342) - P(Z ≤ - 20.5396)

P(Z ≤ 6.8465342) = 1 (Z probability calculator)

P(Z ≤ - 20.5396) = 0 (Z probability calculator)

1 - 0 = 1

3 0

3 years ago

9. simplify the radical expression pleasseee and thank you :)

Vinil7 [7]

Answer:

sqrt 10 / 9

Step-by-step explanation:

gotcha

4 0

3 years ago

Read 2 more answers