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Lera25 [3.4K]
2 years ago
8

Which operation should you perform last in the expression 12 × 42?

Mathematics
2 answers:
GrogVix [38]2 years ago
6 0

Answer:

The order of operations requires that all multiplication and division be performed first, going from left to right in the expression.

Step-by-step explanation:

notsponge [240]2 years ago
3 0
First, consider expressions that include one or
more of the arithmetic operations: addition,
subtraction, multiplication, and division. The
order of operations requires that all
multiplication and division be performed first,
going from left to right in the expression.
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#2 and #3 please. I'm lost
Dennis_Churaev [7]
Alternate means it will be across and on the opposite side, there for the alternate interior angle for 2 would be the same number as the function you're solving.
For example: if you're going to find the alternate interior of 17x+9, it will be 17x+9, the angle on the lower right hand side of the top parallel line.
5 0
3 years ago
A circle is placed in a square with a side length of 10 mm, as shown below. Find the area of the shaded region.
elena-14-01-66 [18.8K]

Answer:

21.5

Step-by-step explanation:

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3 years ago
2x+6=2 <br><br><br> I need help with this plss
Natalka [10]

Step-by-step explanation:

Going to assume you need to know that value of x

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3 years ago
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The bakers made 25 each of lemon, apple, and
g100num [7]

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Step-by-step explanation:

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4 0
3 years ago
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Solve the following problems : Given: S, T, and U are the midpoints of RP , PQ , and QR respectively. Prove: △SPT≅△UTQ.
AleksandrR [38]

Answer:

Hence Proved △ SPT ≅ △ UTQ

Step-by-step explanation:

Given: S, T, and U are the midpoints of Segment RP , segment PQ , and segment QR respectively of Δ PQR.

To prove: △ SPT ≅ △ UTQ

Proof:

∵ T is is the midpoint of PQ.

Hence PT = PQ    ⇒equation 1

Now,Midpoint theorem is given below;

The Midpoint Theorem states that the segment joining two sides of a triangle at the midpoints of those sides is parallel to the third side and is half the length of the third side.

By, Midpoint theorem;

TS║QR

Also, TS = \frac{1}{2} QR

Hence, TS = QU (U is the midpoint QR) ⇒ equation 2

Also by Midpoint theorem;

TU║PR

Also, TU = \frac{1}{2} PR

Hence, TU = PS (S is the midpoint QR) ⇒ equation 3

Now in △SPT and △UTQ.

PT = PQ (from equation 1)

TS = QU (from equation 2)

PS = TU (from equation 3)

By S.S.S Congruence Property,

△ SPT ≅ △ UTQ ...... Hence Proved

6 0
3 years ago
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