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andreyandreev [35.5K]
3 years ago
11

Side ST=5, side US=8, side VW=5, and side XV=8. What side corresponds to side TU and can be used to show that triangle STU is co

ngruent to triangle VWX by SSS?
Mathematics
1 answer:
marishachu [46]3 years ago
6 0
WX has to be congruent to side TU in order for the two triangles to be congruent by SSS.
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PLSS HELP ILL GIVE YOU A BRAINLIEST AND 30 points!
jekas [21]
A :-) 1.) Given - base = 9 cm
height ( alt ) = 12 cm
hypotenuse ( hypo ) = x
Solution -
By Pythagorus theorem
( hypo )^2 = ( base )^2 + ( alt )^2
( x )^2 = ( 9 )^2 + ( 12 ) ^2
( x )^2 = 81 + 144
( x )^2 = 225
( x ) = _/225
( x ) = 15 cm

.:. The value of x ( hypotenuse ) = 15 cm


2.) Given - base = 10 cm
Height = 24 cm
Hypotenuse = x
Solution -
By pythagorus theorem
( hypo )^2 = ( base )^2 + ( alt )^2
( x )^2 = ( 10 )^2 + ( 24 )^2
( x )^2 = 100 + 576
( x )^2 = 676
( x ) = _/676
( x ) = 26

.:. The value of x ( hypotenuse ) = 26 cm


3.) Given - base = 3 cm
Height = 7 cm
Hypotenuse = x
Solution -
By pythagorus theorem
( hypo )^2 = ( base )^2 + ( alt )^2
( x )^2 = ( 3 )^2 + ( 7 )^2
( x )^2 = 9 + 49
( x )^2 = 58
( x ) = _/58
( x ) = 7.6

.:. The value of x ( hypotenuse ) = 7.6 cm


4.) Given - base = 10 cm
Height = 6 cm
Hypotenuse = x
Solution -
By pythagorus theorem
( Hypo )^2 = ( base )^2 + ( alt )^2
( x )^2 = ( 10 )^2 + ( 6 )^2
( x )^2 = 100 + 36
( x )^2 = 136
( x ) = _/136
( x ) = 11.6

.:. The value of x ( hypotenuse ) = 11.6 cm


5.) Given - hypotenuse = 24 cm
height = 6 cm
Base = x
Solution -
By pythagorus theorem
( hypo )^2 = ( base )^2 + ( alt )^2
( 24 )^2 = ( x )^2 + ( 6 )^2
( x )^2 = ( 6 )^2 - ( 24 )^2
( x )^2 = 36 - 576
( x )^2 = -540
( x ) = _/-540
( x ) = 23.2

.:. The value of x ( base ) = 23.2 cm


6.) Given - base = 1 cm
height = 1 cm
hypotenuse = x
Solution -
By pythagorus theorem
( hypo )^2 = ( base )^2 + ( alt )^2
( x )^2 = ( 1 )^2 + ( 1 )^2
( x )^2 = 1 + 1
( x )^2 = 2
( x ) = _/2
( x ) = 1.4

.:. The value of x ( hypotenuse ) = 1.4 cm


7.) Given - hypotenuse = 21 cm
height = 8 cm
Base = x
Solution -
By pythagorus theorem
( hypo )^2 = ( base )^2 + ( alt )^2
( 21 )^2 = ( x )^2 + ( 8 )^2
441 = ( x )^2 + 64
( x )^2 = 64 - 441
( x )^2 = -377
( x ) = _/-377
( x ) = 19.4

.:. The value of x ( base ) = 19.4


8.) given - height = 24 cm
Hypotenuse = 30cm
Base = x
Solution -
By pythagorus theorem
( hypo )^2 = ( base )^2 + ( alt )^2
( 30 )^2 = ( x )^2 + ( 24 )^2
900 = ( x )^2 + 576
( x )^2 = 576 - 900
( x )^2 = -324
( x ) = _/-324
( x ) = 18

.:. The value of x ( base ) = 18 cm


9.) ( i ) lets find ‘x’
Given - base = 9 cm
height = 5 cm
hypotenuse = x
Solution -
By pythagorus theorem
( hypo )^2 = ( base )^2 + ( alt )^2
( x )^2 = ( 9 )^2 + ( 5 )^2
( x )^2 = 81 +25
( x )^2 = 106
( x ) = _/106
( x ) = 10.2

.:. The value of x ( hypotenuse )
= 10.2 cm

( ii ) lets find ‘y’
Given - base = 3 cm
height = 5 cm
Hypotenuse = y
Solution -
By pythagorus theorem
( hypo )^2 = ( base )^2 + ( alt )^2
( y )^2 = ( 3 )^2 + ( 5 )^2
( y )^2 = 9 + 25
( y )^2 = 34
( y ) = _/34
( y ) = 5.8

.:. The value of y ( hypotenuse )
= 5.8 cm

4 0
3 years ago
A 20-foot ladder is leaning against a building. If the bottom of the ladder is sliding along the pavement directly away from the
zaharov [31]

Answer: The top of the ladder is moving down at a rate of 0.303 feet / second

Step-by-step explanation: Please see the attachments below

7 0
3 years ago
Completely factor the given polynomial, if possible. If the polynomial cannot be factored, write NF for your answer.X^3+14x^2+45
vova2212 [387]

Given

x^3+14x^2+45x

Answer

\begin{gathered} x^3+14x^2+45x \\ =x(x^2+14x+45) \\ =x(x^2+5x+9x+45) \\ =x(x+5)(x+9) \end{gathered}

8 0
1 year ago
Amir lent Rs. 600 to Hameed for 2 yrs and Rs.150 to Aman for 4 yrs and recievd altogether from both rs.90 as simple intrest.The
Alja [10]
600 *2*x + 150*4*x = 90

1200x + 600x = 90

1800x = 90

x = 90/1800 = 0.05

x = 5%

Answer: rate of interest = 5%

 
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4 years ago
How would you solve this problem step by step ?<br><br> 4√15(2√2 + √5)
xxTIMURxx [149]

~~4\sqrt{15} \left( 2\sqrt 2 + \sqrt 5 \right)\\\\=8\sqrt{15} \sqrt 2 + 4\sqrt{15} \sqrt 5\\\\=8\sqrt{15\times 2}+4 \sqrt{15 \times 5}\\\\=8\sqrt{30}+4\sqrt{3 \times 5 \times 5}\\\\=8\sqrt{30}  + 4 \sqrt{3\times 5^2}\\\\=8\sqrt{30} + 4\cdot 5 \sqrt 3\\\\=8\sqrt{30} +20\sqrt{3}

4 0
2 years ago
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