If you're looking for x it is 5 which also makes YZ equal 5
Let Fn be the number of ways of arranging such flagpole with the given conditions.
When arranging a flagpole of n feet high, consider the following cases
If the last flag used is a red flag, then the other flags are n-1 foot high, so they can be seen as arranged on a smaller flagpole of n-1 feet high, which can be done in Fn-1 ways.
Similarly, If the last flag used is a gold flag, then the other flags can be seen as arranged on a smaller flagpole of n-1 feet high. This can be done in Fn-1 ways.
If the last flag used is green, the other flags are n-2 feet high, so the flagpole can be arranged in Fn-2 ways.
Using the sum rule, we obtain that Fn = 2Fn-1 + Fn-2 for all n≥3. Listing all the combinations of flags, the initial conditions are F1 = 2 and F2 = 3.
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Answer:
a,
Step-by-step explanation:
thats only a opinion
i think its not right
Answer:
0.86
Step-by-step explanation:
Rounding rules.
4 and below, round down.
5 and above, round up.
We are going to look at the thousandths place to round to the hundredths place.
0.857 -> 0.86
Best of Luck!