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Mice21 [21]
2 years ago
8

Find the geometric mean between 20 and 5

Mathematics
2 answers:
Sholpan [36]2 years ago
3 0
Answer is a
Explanation 5/20
katovenus [111]2 years ago
3 0

The answer is 10.

Step-by-step explanation:

I have the same question on some tests of mine

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Alex777 [14]
8[2] + 6[2] = c[2]
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8 + 6 + 10 = 24 units
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3 years ago
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Consider two​ investments, one earning simple interest and one earning compound interest. If both start with the same initial de
Len [333]

Answer:

Ratio between balances will be:

(x*(1+i)*n)/(x*(1+i)^n)

Where;

x = deposit

%i = interest rate annual

n = years

Step-by-step explanation:

Lets say first deposit is x$ for both investment and annual interest rate for both investment are %i. Also, they stayed under i interest in n years:

Total balance for simple interest is:

Total balance=x*(1+i)*n

How ever total balance for compound interest is:

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6 0
3 years ago
-4 (x + 10) -6 = -3 (x-2)
Luba_88 [7]

Answer:

-52

Step-by-step explanation:

3 0
3 years ago
The coefficient of x^ky^n-k in the expansion of (x+y)^n equals (nk). True or false.
AVprozaik [17]

Answer:

The correct option is;

False

Step-by-step explanation:

The coefficient of x^k·y^(n-k) is nk,   False

The kth coefficient of the binomial expansion, (x + y)ⁿ is  \dbinom{n}{k} = \dfrac{n!}{k!\cdot (n-k)!} = C(n,k)

Where;

k = r - 1

r = The term in the series

For an example the expansion of (x + y)⁵, we have;

(x + y)⁵ = x⁵ + 5·x⁴·y + 10·x³·y² + 10·x²·y³ + 5·x·y⁴ + y⁵

The third term, (k = 3) coefficient is 10 while n×k = 3×5 = 15

Therefore, the coefficient of x^k·y^(n-k) for the expansion  (x + y)ⁿ = C(n,k) not nk

7 0
3 years ago
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