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m_a_m_a [10]
3 years ago
7

What is 4 groups of 12

Mathematics
2 answers:
zhuklara [117]3 years ago
4 0
4×12=48 so it would be 48
Anna35 [415]3 years ago
3 0

4 groups of 12 is just 4 times 12.  Which is 48.  Hope this helped!

-TTL

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SECTION B
lapo4ka [179]

Answer: The median value of data set B is -5.5, which is less than the median value of 3.1 in dataset A.

Step-by-step explanation:

Order the dataset from least to greatest:

-38 → -13 → -9 → -2 → 14 → 28

Then find the values that lies in the middle:

-38 → -13 → <u>-9 → -2</u> → 14 → 28

Since there are 2 values, find the average of those 2 values:

\frac{-9+(-2)}{2} =\frac{-11}{2} =-5.5

The median value = -5.5.

The median value of data set B is -5.5, which is less than the median value of  3.1 in dataset A.

3 0
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Let a = 24, b = 12, and c = 4. Evaluate ac+bc .
seropon [69]

Answer:

144

Step-by-step explanation:

If u multiply 24 x4 it is 96 and when I multiply 12x4 is 48 and u add 96 plus 48 u get 144.

6 0
3 years ago
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What are three different complex fractions that simplify to 1/4
GaryK [48]
I know one of them is 1/2
7 0
3 years ago
The heights in inches of orangutans Are normally distributed with a population standard deviation of 3" and an unknown populatio
CaHeK987 [17]

Answer: The 95% confidence interval is approximately (55.57, 58.43)

======================================================

Explanation:

At 95% confidence, the z critical value is about z = 1.960 which you find using a table or a calculator.

The sample size is n = 17

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The population standard deviation is sigma = 3

The lower bound of the confidence interval is

L = xbar - z*sigma/sqrt(n)

L = 57 - 1.960*3/sqrt(17)

L = 55.5738905247863

L = 55.57

The upper bound is

U = xbar + z*sigma/sqrt(n)

U = 57 + 1.960*3/sqrt(17)

U = 58.4261094752137

U = 58.43

Therefore the confidence interval (L, U) turns into (55.57, 58.43) which is approximate.

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Answer:

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Step-by-step explanation:

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