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Marianna [84]
2 years ago
9

Use the distributive property to fill in the blanks below

Mathematics
2 answers:
Alborosie2 years ago
4 0

Answer:

I think the first one is 8 and the other one is 7 I think

Mrrafil [7]2 years ago
3 0
The first blank is 4 then the second blank is 4 as well.
You might be interested in
Multiply & Simplify.
kipiarov [429]
<span>2a(7a²-3a+9)
=14a^3 - 6a^2 +18a

answer is </span><span>D. 14a³-6a²+18a</span>
3 0
3 years ago
a discount of 15% saved jackie $57 on office supplies. what was the price of the supplies before the discount?
kolbaska11 [484]

Answer:

$38-

Step-by-step explanation:

15% = $57

57 ÷ 3 = 19%

15 ÷ 3 = 5

100 ÷ 5 = 20

19% × 20 = $380

6 0
3 years ago
Allie made the line plot below to show the lengths of strings she cut for her art project.
marishachu [46]

Answer:

1/4, or 0.25 inches

Step-by-step explanation:

You count the dots. The number of dots tell you how many of each length of string she used.

You first find the column with the most dots, and then you find the column with the least. Then you just subtract them, the number of inches it displays on the bottom, 12 1/2 - 12 1/4, which is 1/4. I did this in my head and you can use a calculator if you want.

Thanks for the points, and have a blessed day. Hope this helps.

7 0
2 years ago
Is (x+7) a factor of f(x)= x^3-3x^2+2x-8
nikklg [1K]

Answer:

Step-by-step explanation:

Use synthetic division to answer this.  If the remainder is zero, then we can safely assume the divisor (x + 7) is a factor of the polynomial f(x)= x^3-3x^2+2x-8.

We use -7 as the divisor in synth. div.  This comes from the factor (x + 7):

-7   /    1    3     2     -8

               -7   28  -210

     -------------------------

         1      -4   30   -218

Here, the remainder is -218, not zero, so no, (x+7) is not a factor of f(x)= x^3-3x^2+2x-8.

6 0
3 years ago
I need help pleeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeaseeeeee
UkoKoshka [18]

Answer:

3 option is correct

Step-by-step explanation:

because all the domains and ranges calculation matches in eqn 3

3 0
3 years ago
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