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Vilka [71]
3 years ago
15

Which shows a correct order to solve this story problem?

Mathematics
1 answer:
inessss [21]3 years ago
6 0
The answer is C. If you subtract the lesser amount from the greater amount then you get the difference between the two and how far they were to each other. Maybe Jamal needs to get more exercise to beat Kylie.
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25
Vanyuwa [196]

Step-by-step explanation:

4(2x-1)+3(2x+5)

8x-4+6x+15

8x+6x-4+15

14x+11

4 0
3 years ago
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What is the answer to x/16=45/40
AveGali [126]
The answer is x = 18
5 0
3 years ago
Read 2 more answers
SOLVING SYSTEMS OF EQUATIONS BY SUBSTITUTION.<br><br> 1. 2x+3y=1<br> -3x+y=15
ohaa [14]
2x+3y=1 \\&#10;-3x+y=15 \\ \\&#10;\hbox{from the 2nd equation:} \\&#10;-3x+y=15 \\&#10;y=15+3x \\ \\&#10;\hbox{substitute 15+3x for y in the 1st equation:} \\&#10;2x+3(15+3x)=1 \\&#10;2x+45+9x=1 \\&#10;9x+2x=1-45 \\&#10;11x=-44 \\&#10;x=-4 \\ \\&#10;\hbox{solve one of the equations for y}: \\&#10;2x+3y=1 \\&#10;2 \cdot (-4) + 3y=1 \\&#10;-8+3y=1 \\&#10;3y=1+8 \\&#10;3y=9 \\&#10;y=3 \\ \\&#10;\hbox{the answer:} \\&#10;x=-4 \\&#10;y=3
6 0
3 years ago
Find the 15th term of the arithmetic sequence -5x+3−5x+3, -9x-2−9x−2, -13x-7,.......???
Anna35 [415]

Answer:

- 61x - 67

Step-by-step explanation:

The n th term of an arithmetic sequence is

a_{n} = a₁ + (n - 1)d

where a₁ is the first term and d the common difference

d = - 9x - 2 - (- 5x + 3)

  = - 9x - 2 + 5x - 3

  = - 4x - 5 and a₁ = - 5x + 3, thus

a_{15} = - 5x + 3 + 14(- 4x - 5) = - 5x + 3 - 56x - 70 = - 61x - 67

5 0
4 years ago
PLEEASSEEEE Answer ASAP. Due in 5 Minutes. 25 points!!!!!!!!!
jonny [76]

Answer:

Here we will use the relationships:

a^n*a^m = a^{n + m}

(a^n)^m = a^{n*m}

\frac{a^n}{a^m} = a^{n - m}

And a number:

a^n

is between 0 and 1 if a is positive and larger than 1, and n is negative.

if a is positive and 0 < a < 1, then we need to have n positive such that:

0 < a^n < 1

A) 5^3*5^{-4} = 5^{3 + (-4)} = 5^{-1}

This is between zero and 1,

B) \frac{3^5}{3^{-6}} = 3^{5 - (-6)} = 3^{11}

This is greater than 1, because the exponent is positive.

C) (\frac{1}{4})^3*( \frac{1}{4})^2 = (\frac{1}{4})^{2 + 3} = (\frac{1}{4})^5

Because a is smaller than 1, and the exponent is positive, then the expression is between 0 and 1.

D) \frac{(-7)^5}{(-7)^7} = (-7)^{5 - 7} = -7^{-2}

The exponent is negative (and pair) then the expression is between 0 and 1.

Remember that when the exponent is pair, we always have that:

(-N)^m = (N)^m

So (-7)^-2 = 7^-2

4 0
3 years ago
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