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aivan3 [116]
3 years ago
5

Calculate the average rate of change for the function

Mathematics
1 answer:
mezya [45]3 years ago
7 0

slope = m = \cfrac{rise}{run} \implies \cfrac{ f(x_2) - f(x_1)}{ x_2 - x_1}\impliedby \begin{array}{llll} average~rate\\ of~change \end{array}\\\\[-0.35em] \rule{34em}{0.25pt}\\\\ f(x)= 2(x-2)^2+1\qquad \begin{cases} x_1=-2\\ x_2=4 \end{cases}\implies \cfrac{f(4)-f(-2)}{4-(-2)} \\\\\\ \cfrac{[2(4-2)^2+1]~~ - ~~[2(-2-2)^2+1]}{4+2}\implies \cfrac{[9]~~ - ~~[33]}{6}\implies \cfrac{-24}{6}\implies -4

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Step-by-step explanation:

Since x = 6, which is a positive number, the answer should be of f(x) = x-6.

When x = -6, which is a negative number, then the answer should be f(x) = x+6.

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Mrs. Conrys class Amaryllis grew 2/9 of an inch in 1/6 of a day. How many inches will it grow in one day?
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6 0
3 years ago
You have one type of nut that sells for $2.80/lb and another type of nut that sells for $9.60/lb. You would like to have 20.4 lb
max2010maxim [7]

Answer:11.396Ibs of nuts that cost $9.60/Ib and 9.014Ibs that cost $2.80/Ib

Step-by-step explanation:

First we find the cost of the supposed mixture we are to get by selling it $6.60/Ib which weighs 20.41Ibs

Which is 6.6 x 20.41 = $134.64

Now we label the amount of mixture we want to get with x and y

x = amount of nuts that cost $2.8/Ib

y = amount of nuts that cost $9.6/Ib

Now we know the amount of mixture needed is 20.41Ibs

So x + y = 20.41Ibs

And then since the price of the mixture to be gotten overall is $134.64

We develop an equation with x and y for that same amount

We know the first type of nut is $2.8/Ib

So for x amount we have 2.8x

For the second type of nut that is $9.6/Ib

For y amount we have 9.6y

So adding these to equate to $134.64

2.8x + 9.6y = 134.64

So we have two simultaneous equations

x + y = 20.41 (1)

2.8x + 9.6y = 57.148 (2)

We can solve either using elimination or factorization method

I'm using elimination method

Multiplying the first equation by 2.8 so that the coefficient of x for both equations will be the same

2.8x + 2.8y = 57.148

2.8x + 9.6y = 134.64

Subtracting both equations

-6.8y = -77.492

Dividing both sides by -6.8

y = -77.492/-6.8 =11.396

y = 11.396Ibs which is the amount of nuts that cost $9.6/Ib

Putting y = 11.396 in (1)

x + y = 20.41 (1)

x +11.396 = 20.41

Subtract 11.396 from both sides

x +11.396-11.396 = 20.41-11.396

x = 9.014Ibs which is the amount of nuts that cost $2.8/Ibs

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4 years ago
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