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Mars2501 [29]
2 years ago
12

Given F ( x ) = -2/3 x - 4 What is the zero of this function?

Mathematics
1 answer:
sineoko [7]2 years ago
5 0

Answer:

-4

Step-by-step explanation:

f(0)=(-2/3)(0) - 4

= - 4

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Express jenny’s age in terms of a if jenny is three years less than half of Anne’s age.
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Answer:

If Anne’s age is represented by the variable a then express Jenny’s age in terms of a if Jenny is three years less than half of Anne’s age

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2 years ago
Answer to cheek your knowledge
scZoUnD [109]

Answer:

D - ASA

This should be the answer since FH and IG can be said to be parallel and therefore we can find both alternate angles or a vertical opposite angle with one side given. We know that ΔFHJ is reduced by a factor of 2 to get ΔGIJ.

7 0
2 years ago
Graph the inequality 4x -2y < 8
iris [78.8K]

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8 0
3 years ago
Plz help me get the answer ASAP
Fantom [35]
  1. a=6
  2. 3 times 6 would equal the answer 18
  3. 3(6)=18
  4. 18=18
5 0
2 years ago
Read 2 more answers
Tough one!
frosja888 [35]
Imx->0 (asin2x + b log(cosx))/x4 = 1/2 [0/0 form] ,applying L'Hospital rule ,we get

= > limx->0 (2a*sinx*cosx - (b /cosx)*sinx)/ 4x3 = 1/2 => limx->0 (a*sin2x - b*tanx)/ 4x3 = 1/2 [0/0 form],

applying L'Hospital rule again ,we get,

 = > limx->0 (2a*cos2x - b*sec2x) / 12x2 = 1/2

For above limit to exist,Numerator must be zero so that we get [0/0 form] & we can further proceed.

Hence 2a - b =0 => 2a = b ------(A)

limx->0 (b*cos2x - b*sec2x) / 12x2 = 1/2 [0/0 form], applying L'Hospital rule again ,we get,

= > limx->0 b*(-2sin2x - 2secx*secx.tanx) / 24x = 1/2 => limx->0 2b*[-sin2x - (1+tan2x)tanx] / 24x = 1/2

[0/0 form], applying L'Hospital rule again ,we get,

limx->0 2b*[-2cos2x - (sec2x+3tan2x*sec2x)] / 24 = 1/2 = > 2b[-2 -1] / 24 = 1/2 => -6b/24 = 1/2 => b = -2

from (A), we have , 2a = b => 2a = -2 => a = -1

Hence a =-1 & b = -2
7 0
2 years ago
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