All categories

2 years ago

HELP WILL GIVE BRAINLEST QUICKKK SP and SR are tangent to circle Q. If SP = 10x - 18 and SR = 2x + 6, find x.

Mathematics

1 answer:

lakkis [162]2 years ago

8 0

Answer:

C.3

Step-by-step explanation:

SP and SR are tangent to circle Q.

-> SP = SR

-> 10x - 18 = 2x + 6

-> 10x - 2x = 18 + 6

-> 8x = 24

-> x = 24/8

-> x = 3

You might be interested in

Solve for the given time.

LenaWriter [7]

Answer:

8851.86

Step-by-step explanation:

100-4.3= 95.7%

15000(.957)^12

5 0

2 years ago

Question down below thanks

lara [203]

Answer:

-x + 1 > 3, and 4x + 6 < -2

Step-by-step explanation:

The inequality reads x < -2, so the arrow follows any values that are less than -2. So we need to simplify each inequality in the following options to see which match x < -2.

-4x+3> -5 simplifies to x < 2 so it's wrong

-2x + 4 > -4 simplifies to x < 4 so it's wrong

-x + 1 > 3 simplifies to x < -2, so it's right

2x + 5 < -3 simplifies to x < -4, so it's wrong

4x+ 6 < -2 simplifies to x < -2, so it's right

7 0

3 years ago

Heba ate 1/12 of a box of cereal. Now the box is 3/4 full

vaieri [72.5K]

Answer:

5/6

Step-by-step explanation:

1/12 + 3/4 = 9/12

9/12 + 1/12 = 10/12

simplify 10/12

= 5/6

7 0

2 years ago

Read 2 more answers

The sum of two numbers is -9. The difference of the two numbers is -41. What are the two numbers?

Nataly [62]

Answer:

the two numbers are 16 and -25

Step-by-step explanation:

Let the two numbers be x and y

x+y=-9

x-y=-41

By substitution

y=-9-x

x-(-9-x)=-41

x+9+x=-41

2x=-41-9

2x=-50

x=-25

y=-9-(-25)

y=16

6 0

3 years ago

A rectangular piece of metal is 25 in longer than it is wide. Squares with sides 5 in long are cut from the four corners and the

Licemer1 [7]

Answer:

The original length was 41 inches and the original width was 16 inches

Step-by-step explanation:

Let

x ----> the original length of the piece of metal

y ----> the original width of the piece of metal

we know that

When squares with sides 5 in long are cut from the four corners and the flaps are folded upward to form an open box

The dimensions of the box are

$L=(x-10)\ in\\W=(y-10)\ in\\H=5\ in$

The volume of the box is equal to

$V=(x-10)(y-10)5$

$V=930\ in^3$

$930=(x-10)(y-10)5$

simplify

$186=(x-10)(y-10)$ -----> equation A

Remember that

The piece of metal is 25 in longer than it is wide

$x=y+25$ ----> equation B

substitute equation B in equation A

$186=(y+25-10)(y-10)$

solve for y

$186=(y+15)(y-10)\\186=y^2-10y+15y-150\\y^2+5y-336=0$

Solve the quadratic equation by graphing

using a graphing tool

The solution is y=16

see the attached figure

Find the value of x

$x=16+25=41$

therefore

The original length was 41 inches and the original width was 16 inches

3 0

3 years ago