The correct box plot will have the "whiskers" extending to 24 and 49. The first quartile will be around 28.5 and the third quartile will be around 41.8. The median will be at 34.

**your question didn't include the box plots to choose from, so use this information to find which one it is :)

3 0

3 years ago

1. If u were to draw a tree diagram showing all the possible outcomes for rolling a six sided die twice, how many total outcomes

Furkat [3]

1. 2). 2. 1) 3 * 2 =6

8 0

3 years ago

The area of a rectangular field is 1000 yd2.Two parallel sides are fenced with aluminum at $15/yd. One of the remaining sides is

ioda

Coolio

lw=1000
lets assume that the aluminum sides are the legnth
2 sides
2*15=30
30l=cost of aluminum

steel=10w
wood=(w-10)5=5w-50
we can eliminate the w by solving for w in first relation

lw=1000
divide both sides by l
w=1000/l
sub that for w

10(1000/l)=steel
5(1000/l)-50=wood

wood cost+steel+aluminum cost=total cost
10(1000/l)+5(1000/l)-50+30l=1525
(10000/l)+(5000/l)-50+30l=1525
(15000/l)-50+30l=1525
add 50 to both sides
(15000/l)+30l=1575
times both sides by l
15000+30l²=1575l
minus 1575l from both sides
30l²-1575l+15000=0
factor
(15)(l-40)(2l-25)=0
set each equal to 0
l-40=0
l=40

2l-25=0
2l=25
l=12.5

the there are 2 possible combinations

aluminum=40yd and steel=25yd or
aluminum=12.5yd and steel=80ft
both yield 1000yd² and cost $1525

5 0

3 years ago