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3 years ago

Best path to find the number of centimeters in 1 yard

Mathematics

1 answer:

In-s [12.5K]3 years ago

6 0

Answer:

Convert cenimeters to inches, then inches to feet, then feet to yards

Step-by-step explanation:

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Help! ANSWER #1 please!

nikklg [1K]

The area is 2,772 feet

Hope this helps! Good luck on your homework!!!

4 0

3 years ago

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Solve x^2+2x+7=0 using the quadratic formula.

Aneli [31]

Answer:

$x=-1\pm \sqrt{6}i$

Step-by-step explanation:

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

$x=\frac{-(2)\pm\sqrt{2^2-4(1)(7)}}{2(1)}$

$x=\frac{-2\pm\sqrt{4-28}}{2}$

$x=\frac{-2\pm\sqrt{-24}}{2}$

$x=\frac{-2\pm\sqrt{-1*24}}{2}$

$x=\frac{-2\pm\sqrt{-1}\sqrt{24}}{2}$

$x=\frac{-2\pm i\sqrt{4*6}}{2}$

$x=\frac{-2\pm i\sqrt{4}\sqrt{6}}{2}$

$x=\frac{-2\pm2i\sqrt{6}}{2}$

$x=-1\pm \sqrt{6}i$

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3 years ago

Kenyon earns $105 for mowing 3 lawns. How much<br>would Kenyon earn for mowing 10 lawns?

svp [43]

Answer:

$350

Step-by-step explanation:

3 lawns --------------> $105

find unit rate:

1 lawn -------------> $105 ÷ 3 = $35 per lawn

10 lawns --------> $35 per lawn x 10 lawns = $350

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3 years ago

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The distance between planets in two stellar systems is 1.6x10^6 miles. If a spaceship is able to travel at 8,400 miles per hour,

emmainna [20.7K]

Answer:

Yes it will be able to make the journey in under a year.

Step-by-step explanation:

To find out how many hours it will take $1.6*10^2$ and divide by 8400

$\frac{1.6*10^2}{8400} = 190.476 hr$

So it will take the space ship 190.476 hours to make the trip.

Next, ask our self, how many hours are in a year?

To find out multiply 365 * 24 = 8760 hr

The 365 = number of day in a year. The 24 = number of hours in a day.

Knowing how many hours there are in a year and how long the trip will take tells us that the journey can be made under a year since there are 8760 hours in a year and we know we can make it there in 190.476 hr traveling at 8400 mph

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3 years ago

Carbon-14 has a half-life of 5720 years and this is a first order reaction. If a piece of wood has converted 75% of the carbon-1

Doss [256]

The amount of the substance (At) at any time t is calculated through the equation,
At = (A0)(e^-kt)
where A0 is the initial amount and k is constant.

For the half-life,
ln (At / A0) = ln 0.5 = -k(5270 years)
The value of k is 1.3153x10^-4 / year.
Substituting this value to the same equation, where At = 0.25A0
ln 0.25 = -(1.3153 x 10^-4)(t)
The value of t from this equation is 10540 years. The closest value to this is letter A.

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3 years ago

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