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mylen [45]
3 years ago
5

Patti works at a coffee shop. She usually takes 3/4 h for lunch. One day the shop was very busy and patti’s manager asked her to

shorten her lunch break by 1/6 h. What fraction of an hour did patti take for lunch that day.
Mathematics
1 answer:
siniylev [52]3 years ago
7 0
3/4 - 1/6 = 9/12 - 2/12 = 7/12 h
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An article in Fire Technology investigated two different foam-expanding agents that can be used in the nozzles of firefighting s
UNO [17]

Answer:

Step-by-step explanation:

Hello!

The objective of this experiment is to test if two different foam-expanding agents have the same foam expansion capacity

Sample 1 (aqueous film forming foam)

n₁= 5

X[bar]₁= 4.7

S₁= 0.6

Sample 2 (alcohol-type concentrates )

n₂= 5

X[bar]₂= 6.8

S₂= 0.8

Both variables have a normal distribution and σ₁²= σ₂²= σ²= ?

The statistic to use to make the estimation and the hypothesis test is the t-statistic for independent samples.:

t= \frac{(X[bar]_1 - X[bar]_2) - (mu_1 - mu_2)}{Sa*\sqrt{\frac{1}{n_1} + \frac{1}{n_2 } } }

a) 95% CI

(X[bar]_1 - X[bar]_2) ± t_{n_1 + n_2 - 2}*Sa* \sqrt{\frac{1}{n_1}+\frac{1}{n_2} }

Sa²= \frac{(n_1-1)S_1^2 + (n_2-1)S_2^2}{n_1 + n_2 - 2}= \frac{(5-1)0.36 + (5-1)0.64}{5 + 5 - 2}= 0.5

Sa= 0.707ç

t_{n_1 + n_2 -2: 1 - \alpha /2} = t_{8; 0.975} = 2.306

(4.7-6.9) ± 2.306* (0.707\sqrt{\frac{1}{5}+\frac{1}{5} })

[-4.78; 0.38]

With a 95% confidence level you expect that the interval [-4.78; 0.38] will contain the population mean of the expansion capacity of both agents.

b.

The hypothesis is:

H₀: μ₁ - μ₂= 0

H₁: μ₁ - μ₂≠ 0

α: 0.05

The interval contains the cero, so the decision is to reject the null hypothesis.

<u>Complete question</u>

a. Find a 95% confidence interval on the difference in mean foam expansion of these two agents.

b. Based on the confidence interval, is there evidence to support the claim that there is no difference in mean foam expansion of these two agents?

8 0
3 years ago
A corporate team-building event costs $32, plus an additional $1 per attendee. If there are 66 attendees, how much will the corp
faust18 [17]

Answer:

corporate team-building event cost will cost $98

Step-by-step explanation:

A corporate team-building event costs $32, plus an additional $1 per attendee.

Let cost be C

The expression for the above statement

C($)= 32+n(1)

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So a situation where there are 66 attendees, the total cost will be

C($) = 32 +66(1)

C($) = 32+66

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To figure out the slope you would want to use this formula for 2 of the points: Y2-Y1/X2-X1.

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this would equal 4/6, which simplifies to 2/3

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80% of 80 is 64. Hope this helps:)
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Answer:

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Step-by-step explanation:

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