9514 1404 393
Answer:
r = 1/9
Step-by-step explanation:
First of all, solve the equation for r:
y = rx
y/x = r . . . . . . . divide by x
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Since r is a constant, it will be the same for any corresponding pairs of x and y. It is convenient to choose both x and y as integers, as in the third table entry.
r = y/x = 5/45
r = 1/9 . . . . . . . . . reduced fraction
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<em>Additional comment</em>
It is not a bad idea to check to see that this works with other values of x and y. For the first line of the table, we have x = 11:
y = rx = (1/9)(11) = 11/9 = 1 2/9 . . . . matches the table value
6h + 21 please mark brainliest
The answer to your question is 514
Answer:
A) g(t) = - 16*t² + 80*t
B) domain is ( 0 ≤ t ≤ 5 )
Step-by-step explanation:
A) for the model rocket
h = 0 and v = 80 feet/sec
Then the equation g(t) = -16*t² + v*t + h
became
g(t) = - 16*t² + 80*t + 0 g(t) = - 16*t² + 80*t
B) The equation g(t) = - 16*t² + 80*t is defined for all real numbers then the domain interval for t is ( -∞ , ∞ ). Now in our case, a model rocket was launched is not possible to get negative values for g(t) then the biggest value for t = 5 from
-16*t² + 80*t ≥ 0
-16*t ≥ -80 16*t ≤ 80
t ≤ 5
And the domain is ( 0 ≤ t ≤ 5 )
