1.7 = 1.7
8/5 = 1.6
2% = 0.02
2%, 8/5, 1.7
Answer:
(30,35,0)
Step-by-step explanation:
We are given that
![C(t)=(2t^2,t^3-4t,0)](https://tex.z-dn.net/?f=C%28t%29%3D%282t%5E2%2Ct%5E3-4t%2C0%29)
![t_0=3,t_1=4](https://tex.z-dn.net/?f=t_0%3D3%2Ct_1%3D4)
The velocity of particle,![v(t)=c'(t)=(4t,3t^2-4,0)](https://tex.z-dn.net/?f=v%28t%29%3Dc%27%28t%29%3D%284t%2C3t%5E2-4%2C0%29)
Substitute ![t_0=3](https://tex.z-dn.net/?f=t_0%3D3)
![C(3)=(2(3)^2,(3)^3-4(3),0))=(18,15,0)](https://tex.z-dn.net/?f=C%283%29%3D%282%283%29%5E2%2C%283%29%5E3-4%283%29%2C0%29%29%3D%2818%2C15%2C0%29)
![v(3)=(4(3),3(3)^2-4,0)=(12,23,0)](https://tex.z-dn.net/?f=v%283%29%3D%284%283%29%2C3%283%29%5E2-4%2C0%29%3D%2812%2C23%2C0%29)
The tangent line at t=3 is given by
![l(t)=c(2)+(t-3)v(3)=(18,15,0)+(t-3)(12,23,0)](https://tex.z-dn.net/?f=l%28t%29%3Dc%282%29%2B%28t-3%29v%283%29%3D%2818%2C15%2C0%29%2B%28t-3%29%2812%2C23%2C0%29)
Now, substitute t=4
![l(4)=(18,15,0)+(4-3)+(12,23,0)=(18,12,0)+(12,23,0)](https://tex.z-dn.net/?f=l%284%29%3D%2818%2C15%2C0%29%2B%284-3%29%2B%2812%2C23%2C0%29%3D%2818%2C12%2C0%29%2B%2812%2C23%2C0%29)
![l(4)=(30,35,0)](https://tex.z-dn.net/?f=l%284%29%3D%2830%2C35%2C0%29)
Hence, the position of particle at
=(30,35,0)
Answer:
the answer is about 62
Step-by-step explanation:
Answer:
4 minus a number times three