All categories

2 years ago

Please help ASAP Can someone give me a short summary of the boxer rebellion please?

Mathematics

1 answer:

DaniilM [7]2 years ago

3 0

Answer:

the boxer of the park after the park after the park after the

You might be interested in

7x = 2y solve for y in terms of x <br> Y=?

Vlad1618 [11]

Answer:

7x/2

Step-by-step explanation:

7x=2y

1) Divide both sides by 2:

y=7x/2

8 0

4 years ago

How many radians is 120 degrees?

dezoksy [38]

Answer:

i searched it up and it is 2.0944

6 0

4 years ago

Read 2 more answers

Whats -3x - 9 = -6x+ 18?

Zinaida [17]

Answer:

Step-by-step explanation:

-3x-9=-6x+18

-9x=27

x=3

4 0

3 years ago

Read 2 more answers

Mrs. Monroe is painting her room and she uses 5 gallons of paint. How many pints of paint did she use?

Veseljchak [2.6K]

Answer:

40 pints of paints

Step-by-step explanation:

there are 8 pints in a gallon

8 x 5 = 40

3 0

3 years ago

Read 2 more answers

X/x-2 + x-1/x+1= -1<br> Can someone walk me through the steps of this problem? Much appreciated. :)

stealth61 [152]

Answer:

x = 0 or x = 1

Step-by-step explanation:

Given equation:

$\dfrac{x}{x-2}+\dfrac{x-1}{x+1}=-1$

Multiply the two denominators to get the same denominator:

Multiply the numerator of the first fraction by the denominator of the second fraction to get the new numerator of the first fraction.

Multiply the numerator of the second fraction by the denominator of the first fraction to get the new numerator of the second fraction.

$\implies \dfrac{x(x+1)}{(x-2)(x+1)}+\dfrac{(x-2)(x-1)}{(x-2)(x+1)}=-1$

Add the numerators and keep the denominator so that there is now one fraction:

$\implies \dfrac{x(x+1)+(x-2)(x-1)}{(x-2)(x+1)}=-1$

Simplify the numerator by expanding the brackets:

$\implies \dfrac{x^2+x+x^2-3x+2}{(x-2)(x+1)}=-1$

$\implies \dfrac{2x^2-2x+2}{(x-2)(x+1)}=-1$

Simplify the denominator by expanding the brackets:

$\implies \dfrac{2x^2-2x+2}{x^2-x-2}=-1$

Multiply both sides by the denominator of the left side:

$\implies 2x^2-2x+2=-1(x^2-x-2)$

Simplify and move everything to the left side:

$\implies 2x^2-2x+2=-x^2+x+2$

$\implies 3x^2-3x=0$

Factor:

$\implies 3x(x-1)=0$

Therefore:

$\implies 3x=0 \implies x=0$

$\implies x-1=0 \implies x=1$

Therefore, x = 0 or x = 1

8 0

2 years ago

Read 2 more answers