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madreJ [45]
3 years ago
6

An art teacher is buying clay by the pound. The teacher buys

Mathematics
1 answer:
VMariaS [17]3 years ago
4 0

Answer:

$14.10

Step-by-step explanation:

hope this helps

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X to the 5th power and y to the 6th power over xy to the 2nd power ​
never [62]

\frac{x^5y^6}{(xy)^2}

\frac{x^5y^6}{x^2y^2}

x^{5-2}y^{6-2}

x^3y^4

6 0
4 years ago
What is the approximate value of x in the equation below.<br> log 3 25 = 3x-1
Vinil7 [7]

Answer:

8.666

Step-by-step explanation:

1. add 1 to 25 and cross it out from the other side

2. divide 26 by 3

3. equals 8.6666

6 0
3 years ago
if melissa placed an order for garden gloves ($2.99 each), and rakes (for $16.99 each), and she ordered three times as many glov
ICE Princess25 [194]
G:$2.99
R:$16.99

For every 1R we have 3G.
1R+3G=$16.99+3($2.99)
So 1R+3G=$25.96

If we take $129.80÷$25.96, we get 5.
So let's try 5.

5R+15G=5($16.99)+15($2.99)
So 5R+15G=$129.80



5 0
3 years ago
Wilma is 5 times as old as yvonne. in ten years, yvonne's age will be a third of wilma's age. how old are they now?
SVEN [57.7K]

Using a system of equations, it is found that Wilma is 50 years old and Yvonne is 10 years old.

<h3>What is a system of equations?</h3>

A system of equations is when two or more variables are related, and equations are built to find the values of each variable.

In this problem, the variables are given as follows:

  • Variable x: Wilma's age.
  • Variable y: Yvonne's age.

Wilma is 5 times as old as yvonne, hence:

x = 5y.

In ten years, yvonne's age will be a third of wilma's age, hence:

y + 10 = \frac{1}{3}(x + 10)

Since x = 5y:

y + 10 = \frac{1}{3}(x + 10)

y + 10 = \frac{1}{3}(5y + 10)

3y + 30 = 5y + 10

2y = 20.

y = 10.

Then:

x = 5y = 5 x 10 = 50.

Wilma is 50 years old and Yvonne is 10 years old.

More can be learned about a system of equations at brainly.com/question/24342899

#SPJ1

3 0
2 years ago
Please Need Help Very Badly!!!
kherson [118]

Answer: use a ruler and measure each side multiply by 30 then multiply all of them by each other

hope this helps and if I'm wrong hope you for give me here is some memes

8 0
4 years ago
Read 2 more answers
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