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2 years ago

AC = BC, CP = CQ and <BPQ = 20°<ACP = ?°

Mathematics

1 answer:

Roman55 [17]2 years ago

8 0

Answer: See attached image

Step-by-step explanation:

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Find the area of a right triangle with a base of 38 cm and height of 26 cm.

meriva

Answer:

494cm²

Step-by-step explanation:

A=hbb/2

=26*38/2= 494cm²

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3 years ago

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What is 7 x 2/3 need answer ASAP

Phantasy [73]

Answer:

The answer is

$4 \frac{2}{3}$

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3 years ago

Order the set of numbers from least to greatest : 2.71,2 3/4, 5, 5/2

Sholpan [36]

Answer: 5/2, 2.71, 2 3/4 , 5

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2 years ago

Find the volume of the solid generated by revolving the region bounded by the graphs of the equations about the x-axis. Verify y

mariarad [96]

Answer:

the volume of the solid generated by revolving the region bounded by the graphs of the equations about the x-axis is;

$\frac{\pi }{2} [e^2 - 1 ]$ or 10.036

Step-by-step explanation:

Given the data in the question;

y = $y = e^{(x - 1 )$ , y = 0, x = 1, x = 2.

Now, using the integration capabilities of a graphing utility

y = $y = e_2}^{(x - 1 )_$ , y = 0

Volume = $\pi \int\limits^2_1 ( e^{x-1)^2} - (0)^2 dx$

Volume = $\pi \int\limits^2_1 ( e^{x-1)^2 dx$

Volume = $\pi \int\limits^2_1 e^{2x-2}dx$

Volume = $\frac{\pi }{e^2} \int\limits^2_1 e^{2x}dx$

Volume = $\frac{\pi }{e^2} [\frac{e^{2x}}{2}]^2_1$

Volume = $\frac{\pi }{2e^2} [e^4 - e^2 ]$

Volume = $\frac{\pi }{2} [e^2 - 1 ]$ or 10.036

Therefore, the volume of the solid generated by revolving the region bounded by the graphs of the equations about the x-axis is;

$\frac{\pi }{2} [e^2 - 1 ]$ or 10.036

3 0

3 years ago

A fashion designer wants to know how many new dresses women buy each year. Assume a previous study found the standard deviation

horsena [70]

Answer:

649

Step-by-step explanation:

Given that

Mean number of dresses is 5.5

Standard deviation of the sample, S.D is 1.3

Margin of error, M.E is 0.1

Level of confidence is 95% or 0.95

The formula for margin of error, M.E is

Z * (S.D/√n) , where

Z = Value for level of confidence which is 1.96

Proceeding further, we have

0.1 = 1.96 * (1.3/√n)

0.1 = 2.548 / √n, making √n subject of formula, we have

√n = 2.548 / 0.1

√n = 25.48, squaring both sides

n = 25.48²

n = 649.23

Therefore the number of sample size we're looking for is n = 649.23, when rounded to the nearest integer, we have it to be 649

4 0

3 years ago

AC = BC, CP = CQ and <BPQ = 20°<ACP = ?°​

AC = BC, CP = CQ and <BPQ = 20°<ACP = ?°