Y1 is the simplest parabola. Its vertex is at (0,0) and it passes thru (2,4). This is enough info to conclude that y1 = x^2.
y4, the lower red graph, is a bit more of a challenge. We can easily identify its vertex, which is (-4,0), and several points on the grah, such as (2,-3).
Let's try this: assume that the general equation for a parabola is
y-k = a(x-h)^2, where (h,k) is the vertex. Subst. the known values,
-3-(-4) = a(2-0)^2. Then 1 = a(2)^2, or 1 = 4a, or a = 1/4.
The equation of parabola y4 is y+4 = (1/4)x^2
Or you could elim. the fraction and write the eqn as 4y+16=x^2, or
4y = x^2-16, or y = (1/4)x - 4. Take your pick! Hope this helps you find "a" for the other parabolas.
Answer:
Answer:
EBD= 156
Step-by-step explanation:
Hope it's answer you
Mark as Brainlist
Answer:
200
Step-by-step explanation:
<u>Step 1: Add</u>
1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 10
1 + 2 = 3
3 + 3 = 6
6 + 4 = 10
10 + 5 = 15
15 + 6 = 21
21 + 7 = 28
28 + 8 = 36
36 + 9 = 45
45 + 1 = 46
46 + 2 = 48
48 + 3 = 51
51 + 4 = 55
55 + 5 = 60
60 + 6 = 66
66 + 7 = 73
73 + 8 = 81
81 + 9 = 90
90 + 10 = 100
<em>100</em>
<u>Step 2: Multiply</u>
100 * 2
<em>200</em>
Answer: 200
Are these true and false? I think it's true for both