-2x^2 + 5x -3 =0
Find the discriminate:
In the given formula a = -2, b = 5 and c = -3
The discriminate is found using the formula b^2 - 4(ac)
Replace the letters with their values:
5^2 - 4(-2*-3)
25 - 4*6
25-24 = 1
When the discriminate is greater than or equal to 0, there are two real solutions.
The answer is c) 2
Answer:
no. see below
Step-by-step explanation:
This much of Josh's working is correct:
x^2-6x=7
x^2-6x+9=7+9
(x-3)^2=16
At this point Josh apparently overlooked the fact that he needed to take the square root of both sides of the equation. Had he done that, he would have ...
x -3 = ±4
x = 3+4 . . . or . . . 3 -4
x = 7 or -1
_____
Josh reported values of x that would match ...
x -3 = ±16
He <em>violated the equal sign</em> by taking the square root on the left, and multiplying by ±1 on the right. Doing different operations on the two sides of the equation will mean the value of x is changed to something other than what you're looking for.
The origin is 0,0 the y axis is the line going up, the x axis is the line going like this — the top right is quadrant 1 the one below it is quadrant 2 the one beside that is quadrant 3 and the one above that is quadrant 4
8 goes into 13 1 time. 13-8=5. Bring down the 2. 8 goes into 52 6 times. 52-48=4. Answer is 16 remainder 4.
Check: 16x8=128, +4 remainder equals 132.
