Help??<br> anyone?<br> 7th grade math <br> tysm

Shayla is 5 feet tall and casts a shadow 2 feet long. at the same time, a nearby lamppost casts a shadow 8 feet long. write and

777dan777 [17]

Here is a proportion

5/2 = x/8

2x = 40
/2 /2

x = 20

Hope this helps

6 0

3 years ago

Read 2 more answers

Can you please help me with 23 and 25 I do not understand!!! Please help

adell [148]

when you multiply a number by a value that's greater than 1, that number increases, for example 2 and then we multiply it like 2 * 3, clearly 2*3 is greater than 2.

now when you multiply a number by a value that's lesser than 1, that number decreases, for example 2 and then we multiply it by something like 1/4, so 2 * 1/4 = 1/2, well, clearly 1/2 is smaller than 2, so 1/2 is a decreased value of 2.

23)

we have here 4/7, and then a product, well, the product is 4/7 and 9/10, however 9/10 is less than 1, recall 1 = 10/10, 9/10 is just a tiny bit less than 1.

because we're multiplying 4/7 by some amount less than 1, the product is a smaller value than 4/7, thus

$\bf \cfrac{4}{7}~~>~\left( \cfrac{9}{10}\times \cfrac{4}{7} \right)$

25)

we have here 5/6 and we multiply it by 7/7, wait a minute!!! 7/7 = 1, we're really just multiplying 5/6 by 1 then, what does that give us? well, 5/6 * 1 = 5/6, just the number itself,

$\bf \cfrac{5}{6}~~=~\left( \cfrac{5}{6}\times \cfrac{7}{7} \right)$

7 0

3 years ago

Coffee company wants to make sure that their coffee is being served at the right temperature. If it is too hot, the customers co

andrey2020 [161]

Answer:

The average temperature of coffee in the sample, which is 70.2.

Step-by-step explanation:

The population is all the costumers. The company has determined that they want the average coffee temperature to be 65 degrees C. So, 65 degrees C is the average of the population.

The sample is the 20 orders. The mean $\mu$ of the sample is 70.2C(That is, the mean of the 20 orders0. So, the correct answer is:

The average temperature of coffee in the sample, which is 70.2.

3 0

3 years ago

Math, Help asap

Nadusha1986 [10]

Answer:

Answer:

The correct answer is 2

5 0

3 years ago

Please solve with explanation (high points)

Hunter-Best [27]

Step-by-step explanation:

so, we have a large triangle made of the 2 cables as legs and the ground distance AB as baseline.

the tower is the height to the baseline of that large triangle.

let's call the top of the tower T.

and remember, the sum of all angles in a triangle is always 180°.

we know the angle A = 62°, and angle B = 72°.

assuming that AB is a truly horizontal line that means that the 2 legs (cables) have different lengths, the triangle is not isoceles, and the tower is not in the middle of the baseline.

so, the height (tower) splits the baseline into 2 parts. let's call them p and q.

p + q = 12 m

p = 12 - q

let's simply define that p is the part of the baseline on the A side, and q is the part of the baseline on the B side.

we have now 2 small right-angled triangles the large height (tower) splits the large triangle into.

one has the sides

AT, height (tower), p

angle A = 62°

angle T = 180 - 90 - 62 = 28°

the other has the sides

BT, height (tower), q

angle B = 72°

angle T = 180 - 90 - 72 = 18°

now remember the law of sine :

a/sin(A) = b/sin(B) = c/sin(C)

with the sides and the associated angles being opposite.

p/sin(28) = height/sin(62)

q/sin(18) = height/sin(72)

we know from above that

p = 12 - q

so,

(12 - q)/sin(28) = height/sin(62)

height = (12 - q)×sin(62)/sin(28)

q/sin(18) = height/sin(72)

height = q×sin(72)/sin(18)

and therefore, as height = height we get

(12 - q)×sin(62)/sin(28) = q×sin(72)/sin(18)

(12 - q)×sin(62)×sin(18) = q×sin(72)×sin(28)

12×sin(62)×sin(18) - q×sin(62)×sin(18) =

= q×sin(72)×sin(28)

12×sin(62)×sin(18) = q×sin(72)×sin(28) + q×sin(62)×sin(18) =

= q×(sin(72)×sin(28) + sin(62)×sin(18))

q = 12×sin(62)×sin(18) / (sin(72)×sin(28) + sin(62)×sin(18))

q = 4.551603755... m

p = 12 - q = 7.448396245... m

height = q×sin(72)/sin(18) = 14.00839594... m ≈ 14 m

the cell tower is about 14 m tall.

7 0

2 years ago

Help?? anyone? 7th grade math tysm