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DaniilM [7]
2 years ago
14

Help please I’d appreciate it

Mathematics
1 answer:
valentinak56 [21]2 years ago
7 0

Answer:

I think it would be (5,6)

Step-by-step explanation:

The formula is (y,-x).

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lisov135 [29]
The answer is D because of the slope. 
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3 years ago
Log(x) + log(x+2) = log 3
statuscvo [17]

Answer:

x=1 and -3

Step-by-step explanation:

log(x)+log(x+2)=log(3)

log(x(x+2))=log(3)

x(x+2)=3, simple quadratic. x=-3 and 1. Answered by Gauthmath

3 0
2 years ago
Find the absolute maximum and minimum values of the following functions on the given curves functions:
bagirrra123 [75]

Answer:

Solution has explained below:

Step-by-step explanation:

(a) f(x,y) = x+y

To find out the maximum and minimum values, we need to find first and second derivatives, we have

fx= 1, fx₁=0 and

fy= 1 and fyy=0

For stationary points fx=fy=0, which gives,

1=1=0, so that there is just one stationary point, (x,y)=(0,0)

If  fx₁  < 0 and fyy < 0, function is maximum

If  fx₁ > 0 and fyy > 0, function is minimum.

(b) g(x,y) = xy

Sol: To find out the maximum and minimum values, we need to find first and second derivatives, we have

fx= 1 and fy  = 1

fx₁ = 0 and fyy =0

for stationary points fx = fy =0, which gives 1=1=0, so that there is just one stationary points, (x,y) =(0,0)

If fx₁ < 0 and fyy < 0, function is maximum.

If  fx₁  > 0 and fyy> 0, function is minimum.

c) h(x,y) = 2x2 + y2

sol: To find out the maximum and minimum values, we need to find first and second derivatives, we have

fx = 4x  and fy = 2y

fx₁= 4  and fyy = 2

Now, taking fx = 0 and fy = 0

Gives x=0 and y=0,

Stationary points are (x,y) = (0,0)

If fx₁ < 0 and fyy < 0, solution is maximum,

If fx₁ > 0 and fyy > 0, solution is minimum,

Here, fx₁ = 4 > 0 and fyy = 2 > 0.

6 0
3 years ago
Which of the following is the equation for a circle with a radius of r and center at (h,v)
Lorico [155]
Are there any answer choices
6 0
3 years ago
Read 2 more answers
Which angle is vertical to BEC?
Lostsunrise [7]

Answer:

<AED

Step-by-step explanation:

Ima be real I cant really explain but i think that's right

3 0
3 years ago
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