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Dima020 [189]
3 years ago
7

∠5 ​ and​ ​ ∠6 ​ ​are complementary angles. m∠5=13°

Mathematics
2 answers:
Hatshy [7]3 years ago
6 0
Since they are complementary angles, then the sum of the measure of both angles is 90
So, M/_5 + m/_6 = 90
13+ X = 90
x=77
measure of angle 6 is 77
Alex73 [517]3 years ago
6 0

Answer:

77

Step-by-step explanation:

i took the test

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Cos(theta) = - 3/4 and is in the 3rd quadrant, find the following:
elena-14-01-66 [18.8K]

Answer:

\begin{gathered} sin(\theta)=\frac{-\sqrt{7}}{4} \\ cos(\theta)=-\frac{3}{4} \\ tan(\theta)=\frac{\sqrt{7}}{3} \\ csc(\theta)=-\frac{4}{\sqrt{7}} \\ sec(\theta)=-\frac{4}{3} \\ cot(\theta)=\frac{3}{\sqrt{7}} \end{gathered}

Step-by-step explanation:

If theta is in the third quadrant, draw the diagram to easily identify the other trigonometric relations:

Solve for the missing leg of the triangle, using the Pythagorean theorem:

\begin{gathered} \text{ adjacent}^2+\text{ opposite}^2=\text{ hypotenuse}^2 \\ -3^2+\text{ opposite}^2=4^2 \\ \text{ opposite=}\sqrt{16-9} \\ \text{ opposite=}\sqrt{7} \end{gathered}

Therefore, for the trigonometric relationships:

\begin{gathered} \text{ sin\lparen}\theta)=\frac{opposite}{hypotenuse} \\ \text{ cos\lparen}\theta)=\frac{adjacent}{hypotenuse} \\ tan(\theta)=\frac{opposite}{adjacent} \\ csc(\theta)=\frac{hypotenuse}{opposite} \\ sec(\theta)=\frac{hypotenuse}{adjacent} \\ cot(\theta)=\frac{adjacent}{opposite} \end{gathered}

Now, substitute and solve for the relations:

\begin{gathered} sin(\theta)=\frac{-\sqrt{7}}{4} \\ cos(\theta)=-\frac{3}{4} \\ tan(\theta)=\frac{\sqrt{7}}{3} \\ csc(\theta)=-\frac{4}{\sqrt{7}} \\ sec(\theta)=-\frac{4}{3} \\ cot(\theta)=\frac{3}{\sqrt{7}} \end{gathered}

7 0
1 year ago
Write the equation in slope-intercept form, for the line that would coincide with (be in line with) line segment AB.
Llana [10]

Answer:

y=2

Step-by-step explanation:

We are finding the equation of the line that coincide with line segment AB.

So, we can find the equation by using points A and B.

A\rightarrow(-3,2)\\B\rightarrow)(1,2)

Slope of line (m) = \frac{y_2-y_1}{x_2-x_1} = \frac{2-2}{1-(-3)} = 0

Since slope = 0, therefore the line is parallel to x-axis.

The equation of line  is given by y=mx+b

where m is slope and b is y-intercept.

So equation of line AB:

where m=0 and b=2

y=(0)x+2

y=0+2

y=2

8 0
3 years ago
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