Question

Hunter is 35 years older than Andrew. After 5 years Hunter will be twice Andrew's age. Find the present age of both.

Answer 1

Answer:

Let h represent Hunter's Age

Let a represent Andrew's Age.

So that means that

h=35+a+5

because he already is 35

we add Andrew's Age

And we add 5 for 5 extra years

Therefore,

35 + 5 + a = 2(a + 5)

35+5=40.

40+a = 2a+10

Substract the a

40 = a+10

Subtract 10

30 = a

If Andrew's age is 30, going back to our first equation,

h = 35 + 30 (previously a) + 5

Hunter's Age = 65

Andrew's Age = 30

Hope it helped!

Answer 2

Answer:

Andrew is 30 years old. Hunter is 65 years old.

Step-by-step explanation:

we can set up 2 equations:

h = 35 + a

h+5 = 2(a+5)

Solve for h in the second equation.

h + 5 = 2a + 10; h = 2a + 5

now set the 2 equations = to each other

2a + 5 = 35 + a

solve for a by combining like terms

a + 5 = 35

a = 30

so Andrew is 30 and Hunter is 35 + 30 = 65.

Sp in 5 years Andrew is 35 and Hunter is 70 (twice A's age)