Question

The height of a ball thrown vertically upward from a rooftop is modelled by h(t)= -4.8t^2 + 19.9t +55.3 where h (t) is the balls height of above the ground, in meters, at time t seconds after the thrown. Determine the maximum height of the ball. ( in numerical value)

Answer 1

By applying the quadratic formula and discriminant of the quadratic formula, we find that the maximum height of the ball is equal to 75.926 meters.

How to determine the maximum height of the ball

Herein we have a quadratic equation that models the height of a ball in time and the maximum height represents the vertex of the parabola, hence we must use the quadratic formula for the following expression:

- 4.8 · t² + 19.9 · t + (55.3 - h) = 0

The height of the ball is a maximum when the discriminant is equal to zero:

19.9² - 4 · (- 4.8) · (55.3 - h) = 0

396.01 + 19.2 · (55.3 - h) = 0

19.2 · (55.3 - h) = -396.01

55.3 - h = -20.626

h = 55.3 + 20.626

h = 75.926 m

By applying the quadratic formula and discriminant of the quadratic formula, we find that the maximum height of the ball is equal to 75.926 meters.

To learn more on quadratic equations: brainly.com/question/17177510

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