The height of a ball thrown vertically upward from a rooftop is modelled by h(t)= -4.8t^2 + 19.9t +55.3 where h (t) is the balls

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The height of a ball thrown vertically upward from a rooftop is modelled by h(t)= -4.8t^2 + 19.9t +55.3 where h (t) is the balls

height of above the ground, in meters, at time t seconds after the thrown. Determine the maximum height of the ball. ( in numerical value)

Mathematics

1 answer:

nikitadnepr [17] · Answer 1 · 2023-10-17T07:59:31+03:00

By applying the quadratic formula and discriminant of the quadratic formula, we find that the maximum height of the ball is equal to 75.926 meters.

<h3>How to determine the maximum height of the ball</h3>

Herein we have a quadratic equation that models the height of a ball in time and the maximum height represents the vertex of the parabola, hence we must use the quadratic formula for the following expression:

- 4.8 · t² + 19.9 · t + (55.3 - h) = 0

The height of the ball is a maximum when the discriminant is equal to zero:

19.9² - 4 · (- 4.8) · (55.3 - h) = 0

396.01 + 19.2 · (55.3 - h) = 0

19.2 · (55.3 - h) = -396.01

55.3 - h = -20.626

h = 55.3 + 20.626

h = 75.926 m

By applying the quadratic formula and discriminant of the quadratic formula, we find that the maximum height of the ball is equal to 75.926 meters.

To learn more on quadratic equations: brainly.com/question/17177510

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