Wow... what grade are you even in to be getting a problem like that? that's a difficult one...
(4/9)/x= 12
Multiply both sides by x
4/9=12x
Divide both sides by 12
(4/9)*(1/12)= 4/108
4/108= 1/27
Final answer: 1/27


Find the values of x for which the denominator is equal to zero for y=3x+5/x-6.
x = −5
x = 6
<h2>x = −6</h2>
therefore the answer is
<h2>x = −6</h2>


(ノ^_^)ノ
<span>Given the two end of the diameter of the circle, we are able to compute the center of the circle as 0.5*[(-1,3)+(7,-7)]=(3,-2). The radius of the circle is 0.5*sqrt[(-1-7)^2+(3+7)^2]=sqrt(41). Therefore the equation of the circle is (x-3)^2+(y+2)^2=41.</span>
Step-by-step explanation:
4+2+2+4+5 - 17
in nearest ten - 100 but i am not sure