Both the numerator and denominator approach 0, so this is a candidate for applying L'Hopital's rule. Doing so gives
This again gives an indeterminate form 0/0, but no need to use L'Hopital's rule again just yet. Split up the limit as
Now recall two well-known limits:
Compute each remaining limit:
So, the original limit has a value of
2/3 + 2/3 + 1/3 + 1/3 - 0 = 2
Answer:
The values of a and b are:
Step-by-step explanation:
We know that the slope-intercept form of the line equation
y = ax+b
where
From the diagram of the line graph, we can fetch the two points
Determining the slope between (0, 2) and (-1, 0)
Thus, the value of a = 2
We know that the value of the y-intercept can be determined by setting x = 0, and determining the corresponding value of y.
From the graph, it is clear
at x = 0, y = 2
Thus, the y-intercept b = 2
now substituting a = 2 and b = 2 in the slope-intercept form of the line equation
y = ax+b
y = 2x + 2 ∵ a = 2 , b = 2
Thus, the line of equation is:
y = 2x+2
now comparing with y = ax+b
Here:
a = 2
b = 2
Therefore, the values of a and b are: