Answer:y=-2x+0
Step-by-step explanation:
Answer:
Jynessa wants to order these fractions: StartFraction 4 over 9 EndFraction, two-thirds, one-sixth, Negative 2 and one-half. What should she use as her common denominator? 6 9 12 18Jynessa wants to order these fractions: StartFraction 4 over 9 EndFraction, two-thirds, one-sixth, Negative 2 and one-half. What should she use as her common denominator? 6 9 12 18Jynessa wants to order these fractions: StartFraction 4 over 9 EndFraction, two-thirds, one-sixth, Negative 2 and one-half. What should she use as her common denominator? 6 9 12 18Jynessa wants to order these fractions: StartFraction 4 over 9 EndFraction, two-thirds, one-sixth, Negative 2 and one-half. What should she use as her common denominator? 6 9 12 18Jynessa wants to order these fractions: StartFraction 4 over 9 EndFraction, two-thirds, one-sixth, Negative 2 and one-half. What should she use as her common denominator? 6 9 12 18Jynessa wants to order these fractions: StartFraction 4 over 9 EndFraction, two-thirds, one-sixth, Negative 2 and one-half. What should she use as her common denominator? 6 9 12 18Jynessa wants to order these fractions: StartFraction 4 over 9 EndFraction, two-thirds, one-sixth, Negative 2 and one-half. What should she use as her common denominator? 6 9 12 18
Step-by-step explanation:
Answer:
V =48 cm^3
Step-by-step explanation:
The volume of a prism is given by
V = l*w*h
V = 3*4*4
V =48 cm^3
Answer:
Step-by-step explanation:
Thank your for revising and improving the image.
Assuming DF is a straight line,
Given E is the mid-point of DF
mCE = mGF
CE || GF
Then
mDE = mEF (E midpoint of DF)
Angle DEC = Angle EFG (corresponding angle, DF transversal of parallel lines CE and GF)
mCE = mGF (given)
Then triangles DCE and EGF are congruent by reason SAS (side-angle-side)
The value of q(x) is 
The value of r(x) is 
Explanation:
The given expression is 
We need to rewrite the expression in the form of 
Simplifying the expression, we get,

Separating the fractions, we have,

-----------(1)
Now, we shall further simplify the term
, we get,

Common out 5 from the numerator, we have,

Substituting the value
in the equation(1), we get,

Thus, the expression
is in the form of 
Hence, we have,

and
