Let X be the random variable denoting the number of successful throws.
Here X~ Binomial Distribution with n = 5 and p = 0.80.
the probability of her missing 3 (or more) free throws out of 5
= P ( X ≤ 2)
= P (X= 0) + P(X= 1) + P(X= 2)
=0.00032 + 0.0064 + 0.0512
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= 0.05792
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Answer:
Step-by-step explanation:
9514 1404 393
Answer:
-2x +4
Step-by-step explanation:
We can write the polynomial p(x) in terms of the factors (x+2) and (x-3) as ...
p(x) = (x+2)(x-3)q(x) +ax +b
Where ax+b is the remainder from division by x^2 -x -6 = (x+2)(x-3). The values of 'a' and 'b' can be found from ...
p(-2) = 8 = -2a +b
p(3) = -2 = 3a +b
Subtracting the first equation from the second gives ...
(3a +b) -(-2a +b) = (-2) -(8)
5a = -10
a = -2
Then the first equation tells us ...
8 = -2(-2) +b
4 = b
So, the remainder from division by (x^2 -x -6) is (-2x +4).
Answer:
Step-by-step explanation:
we have that
------> by supplementary angles
Substitute the values and solve for x
Find the value of angle R
Find the value of angle Q
