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lilavasa [31]
3 years ago
7

Two buses leave towns 1631km apart at the same time and travel toward each other. one bus travels 17 /kmh slower than the other.

if they meet in 7 hours, what is the rate of each bus?
Mathematics
1 answer:
Blababa [14]3 years ago
5 0
Suppose one bus travels at x km/h, the second bus is 17 km/h slower so it is x-17
the first bus travels a total of 7x km, the second bus travels 7(x-17)km, together they travel the total distance of 1631 km
7x + 7(x-17) =1631
7x + 7x -119 =1631
14x=1750

x=125
x-17=108

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Answer:

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Step-by-step explanation:

Let the triangle be ABC. Given two sides and an included angle, let us apply the cosine rule to determine the third length.

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B. Given that B = 60^{o}, then let us apply the Sine rule to determined the measure of A.

\frac{a}{SinA} = \frac{b}{SinB}

So that,

\frac{6}{Sin A} = \frac{5.2}{Sin60^{o} }

Sin A = \frac{0.886*6}{5.2}

Sin A = 0.99923

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Since the sum of angle in a triangle = 180^{o}.

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A + B + C = 180^{o}

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C = 180^{o} - 148^{o}

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C = 32^{o}

Thus,

A = 88^{o}, B = 60^{o} and C = 32^{o}.

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