Greater than (I'm like 80% sure of my answer)
Answer:
a) The cost of ribeye steak dinners is $ 16.96.
b) The cost of grilled salmon dinners is $ 23.37.
Explanation:
Let the cost for ribeye steak dinners be m and cost for grilled salmon dinners be n.
A waitress sold 10 ribeye steak dinners and 18 grilled salmon dinners, totaling $590.39 on a particular day.
So, we have
10 m + 18 n = 590.39 -------equation 1
Another day she sold 22 ribeye steak dinners and 9 grilled salmon dinners, totaling $583.49
So, we have
22 m + 9 n = 583.49 -------equation 2
equation 2 x 2
44 m + 18 n = 1166.98 -------equation 3
equation 3 - equation 1
44 m + 18 n - ( 10 m + 18 n ) = 1166.98 - 590.39
m = 16.96 $
Substituting in equation 1
22 x 16.96 + 9 n = 583.49
n = 23.37 $
a) The cost of ribeye steak dinners is $ 16.96.
b) The cost of grilled salmon dinners is $ 23.37.
Answer:
x = 12
Step-by-step explanation:
130 + y = 180 {linear pair}
y = 180 - 130
y = 50°
3x - 6 +8x + 4 + 50 = 180 {Angle sum property of triangle}
3x + 8x - 6 + 4 + 50 = 180 {Combine like terms}
11x + 48 = 180
11x = 180 - 48
11x = 132
x = 132/11
x = 12°
For Sammie the equation would be S=3N.
If Nora (N) has 4 goldfish, you substitute N=4 into the previous equation to find out how many goldfish Sammie has.
> S= 3 x 4
= 12
The next part of the question is asking you how many goldfish do Sammie and Nora have in all. If Sammie has 12 goldfish and Nora has 4 goldfish, the equation would be 12 + 4= 16
The answer would be 16 goldfish in total.
Answer: 20%
Step-by-step explanation:
25 = 100%
25/5 = 5
100/5 = 20
That means 80% passed and 20% didnt.
