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Tcecarenko [31]
2 years ago
9

The following question find the value of the variables. If your answer is not an integer leave it in simplest radical form

Mathematics
1 answer:
Margarita [4]2 years ago
3 0

Answer:

option 4

Step-by-step explanation:

using the sine/ cosine ratios in the right triangle and the exact values

cos30° = \frac{\sqrt{3} }{2} , sin30° = \frac{1}{2} , then

cos30° = \frac{adjacent}{hypotenuse} = \frac{x}{20\sqrt{3} } = \frac{\sqrt{3} }{2} ( cross- multiply )

2x = 20\sqrt{3} × \sqrt{3} = 20 × 3 = 60 ( divide both sides by 2 )

x = 30

and

sin30° = \frac{opposite}{hypotenuse} = \frac{y}{20\sqrt{3} } = \frac{1}{2} ( cross- multiply )

2y = 20\sqrt{3} ( divide both sides by 2 )

y = 10\sqrt{3}

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The sides of a triangle are 1, x, and x2. what are possible values of x?
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The possible lengths of the sides are
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