import java.util.Scanner;
public class JavaApplication57 {
public static void main(String[] args) {
Scanner scan = new Scanner(System.in);
System.out.println("Enter two numbers:");
int num1 = scan.nextInt();
int num2 = scan.nextInt();
while (num1 <= num2){
if (num1 %2 == 0){
System.out.print(num1+" ");
}
num1+=1;
}
}
}
I hope this helps!
A program that repeatedly prompts a user for integer numbers :
biggest = none
smallest = none
while True:
input = raw_input(“Enter a number:”)
if(input == “done” break
try:
number = float(inp)
except ValueError:
print “Please enter only numbers”
else
if smallest is None:
smallest = number;
biggest = number;
elif number < smallest:
smallest = number
elif num > largest:
largest = number
Print “Greatest is “, biggest
Print “Smallest is”, smallest
In this program an input is obtained, if it is equal to the word “done”, then the program stops b printing greatest and smallest number in the given input.
If invalid inputs are given then user is prompted to enter valid number. Otherwise the value of smallest and greatest are calculated according to the input using if-else construct.
"My 2 in 1 laptop/tablet goes black and does this weird glitching thing..."
2-in-1 has a bunch of connections bet the keyboard n screen. its weaker than a laptop cuz' the keyboard is detachable. bad news if u have a flaky connection there.
if its brand new or under warranty, i wuld send it back. good luck!
Hello! I believe the answer for this is "True"!
