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ahrayia [7]
3 years ago
12

8. A pattern of being late for work or for appointments is usually

Computers and Technology
1 answer:
Reika [66]3 years ago
7 0
As I see it, I think people are being late because of different reasons. I used to come late, but when I realized it annoys other people, I tried to change this bad habit and it required a lot of work (but I managed to to that). It is not easy to change bad habits with a little work.
Some people are late because they do not realize it really annoys people and I think problem is related to the type of personality. Some people are late, because they have a lot to do, some are late because they are lazy. I would choose answer B.
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An Oven Is Just A Spicy Refrigerator? Yes Or No??
Marianna [84]

Answer:

No

Explanation:They both have different actions

3 0
3 years ago
Read 2 more answers
Hello, I've tried everything and I cannot get this code to be fair. I need help. Can someone provide guidance so I can understan
Liula [17]

A program that takes a date as input and outputs the date's season. The input is a string to represent the month and an int to represent the day is given below:

<h3>The Program</h3>

input_month = input()

input_day = int(input())

months= ('January', 'February','March', 'April' , 'May' , 'June' , 'July' , 'August' , 'September' , "October" , "November" , "December")

if not(input_month in months):

  print("Invalid")

elif input_month == 'March':

   if not(1<=input_day<=31):

       print ("Invalid")

   elif input_day<=19:

       print("Winter")

   else:

      print ("Spring")

elif input_month == 'April' :

   if not(1<=input_day<=30):

       print("Invalid")

   else:

      print("Spring")

elif input_month == 'May':

   if not(1<=input_day<=31):

       print("Invalid")

   else:

       print("Spring")

elif input_month == 'June':

   if not(1<=input_day<=30):

       print("Invalid")

   elif input_day<=20:

       print ("Spring")

   else:

       print("Summer")

elif input_month == 'July' or 'August':

   if not(1<=input_day<=31):

       print("Invalid")

   else:

       print("Summer")

elif input_month == 'September':

   if not(1<=input_day<=30):

       print("Invalid")

  elif input_day<=21:

       print ("Summer")

   else:

       print ("Autumn")

elif input_month == "October":

   if not(1<=input_day<=31):

      print("Invalid")

   else:

       print("Autumn")

elif input_month == "November":

   if not(1<=input_day<=30):

       print("Invalid")

   else:

       print ("Autumn")

elif input_month == "December":

   if not(1<=input_day<=31):

       print("Invalid")

   elif input_day <=20:

       print ("Autumn")

   else:

       print ("Winter")

elif input_month == 'January':

   if not(1<=input_day<=31):

       print("Invalid")

   else:

       print("Winter")

elif input_month == "February":

   if not(1<=input_day<=29):

       print("Invalid")

   else:

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Read more about programming here:

brainly.com/question/23275071

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5 0
1 year ago
AD and BC are equal perpendiculars to a line segment AB (see figure). Show that CD
Simora [160]
Show the picture to answer the question
7 0
3 years ago
For window 7 explain the steps you will use to find the available program you will list.
Alex_Xolod [135]
Follow these steps.
1. Make sure that your pc is on.
2. Press your Window key - on your bottom left of your keyboard you will see a window key. 
3. After pressing it will show a tab on your bottom left of your monitor.
4. On that tab you will see an (All Programs) text.
5. Click it and it will show all programs available on your pc.
8 0
3 years ago
Write a bool function isPalindrome that takes one string parameter and returns true if that string is a palindrome and false oth
kkurt [141]

Answer:

Here is the bool function isPalindrome:

bool isPalindrome(string s)

{  bool palindrome;      

 int j;

 int len = s.length();

 for (int i =0, j= len-1; i < len/2; i++, j--)  

   if (s[i] == s[j])

     palindrome = true;  

   else

     palindrome = false;

 return palindrome; }

Explanation:

The bool function isPalindrome takes a string as parameter and returns true if the string is a palindrome or false if the string is not palindrome. The string variable s holds the string value. In function isPalindrome, there is a bool type variable palindrome. bool is a data type which is used to hold values true or false which is then stored in the palindrome variable.

Next it is being found that how many characters are there in the input string using length() function which returns the length of the string. The length of the string is stored in int type variable len.

Next the for loop starts which has two variables i and j where i starts at 0 position of the input string and j starts at the last position of the string. These two variables move or traverse along the string this way. i variable stops when half the length of the input string is reached. At the end of every iteration i moves forward by the increment of its value to 1 and j moves backwards by the decrement  of its value to 1.

Every the body of  the loop executes, there is an if condition in the body of the loop which checks if the string is a palindrome. This is checked by matching the character at position/index i with the character at position j of the string. This will continue character by character until the i reached half the length of the input string and if every character in i was matched to every character in j then palindrome = true; statement is executed which returns true as the string is a palindrome otherwise palindrome = false; is returned as the string is not a palindrome.

For taking input string from the user and to check if the function isPalindrome() works correctly a main() function is written which takes input string from the user and reads in variable str calls isPalindrome() function. If the string is palindrome then the cout statement in main() function prints the message: String is a palindrome and if the input string is not a palindrome the the following message is displayed in the output screen: String is not a palindrome

int main()

{

string str;

cout<<"Enter a string: ";

cin>>str;

if(isPalindrome(str))

cout<<"String is a palindrome";

else

cout<<"String is not a palindrome";

}

The screenshot of the program along with the output is attached.

7 0
3 years ago
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