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2 years ago

5

A boat is worth $10,000 when it is 5 years old and $4,000 when it is 8 years old. What is the rate of depreciation? PLEASE ANSWE

R ASAP
• $2,500
• $1,500
• $1,000
• $ 2,000

1 answer:

romanna [79]2 years ago

4 0

Answer:

$2,000

Step-by-step explanation:

10,000-4,000=6,000

8-5=3

The value decreased 6,000 over the course of 3 years

6,000/3=2000

The value decreased by 2,000 per year.

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What is the perimeter of triangle PQR.

shutvik [7]

Answer:

Opps i am really sorry i donot know it

7 0

3 years ago

A journal article reports that a sample of size 5 was used as a basis for calculating a 95% CI for the true average natural freq

oksano4ka [1.4K]

Answer:

$Lower = 231.134- 3.098=228.036$

$Upper = 231.134+ 3.098=234.232$

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X$ represent the sample mean for the sample

$\mu$ population mean (variable of interest)

s represent the sample standard deviation

n=5 represent the sample size

Solution to the problem

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

And for this case we know that the 95% confidence interval is given by:

$\bar X=\frac{233.002 +229.266}{2}= 231.134$

And the margin of error is given by:

$ME = \frac{233.002 -229.266}{2}= 1.868$

And the margin of error is given by:

$ME= t_{\alpha/2} \frac{s}{\sqrt{n}}$

The degrees of freedom are given by:

$df = n-1 = 5-1=4$

And the critical value for 95% of confidence is $t_{\alpha/2}= 2.776$

So then we can find the deviation like this:

$s = \frac{ME \sqrt{n}}{t_{\alpha/2}}$

$s = \frac{1.868* \sqrt{5}}{2.776}= 1.506$

And for the 99% confidence the critical value is: $t_{\alpha/2}= 4.604$

And the margin of error would be:

$ME = 4.604 *\frac{1.506}{\sqrt{5}}= 3.098$

And the interval is given by:

$Lower = 231.134- 3.098=228.036$

$Upper = 231.134+ 3.098=234.232$

6 0

3 years ago

The answer and explanation to question 1

xxMikexx [17]

Answer:

20, 31, 33, 35, 55, 57, 58, 59, 72, 73, 79, 86, 87, 88

Step-by-step explanation:

The data set is split by digit. So 2|0 becomes 20. 5|5 becomes 55. Using this method, the data set is

20, 31, 33, 35, 55, 57, 58, 59, 72, 73, 79, 86, 87, 88

7 0

3 years ago

the length of a rectangle is 3cm more than the width. find the length and the width if the perimeter of the rectangle is 98cm.

laila [671]

The perimeter of a rectangle is <u>length + length + width + width</u>.

We know that the length of a rectangle is 3cm more than its width, which gives us the equation: (l for length and w for width)

l = 3 + w

We also know that the perimeter of the rectangle is 98cm, which gives us the equation:

98 = 2l + 2w (equation for perimeter of a rectangle as noted above)

We can divide both sides of this equation by 2 to get:

49 = l + w

Now we'll stick l = 3 + w into the above equation, which gives us:

49 = 3 + w + w

which simplifies to 49 = 3 + 2w.

Now we'll subtract 3 from both sides:

49 - 3 = 46

3 + 2w - 3 = 2w

which gives us 46 = 2w.

Dividing both sides by 2 gives us 23 = w.

Substituting w = 23 into the equation l = 3 + w gives us:

l = 3 + 23

l = 26cm.

Let's check our answer. 26cm is 3cm more than 23cm. 26cm + 26cm + 23cm + 23cm gives us 98cm. The length is 26cm and the width is 23cm.

7 0

3 years ago

Gage is building a model rocket for a science fair project. He attaches a nosecone to a cylindrical body to form the rocket's fu

denpristay [2]

Answer:

305.78 in2

Step-by-step explanation:

The rocket has two parts: one is a cylinder and the other is a cone.

To find the total volume of the rocket, we need to find firstly the volume of each part.

The cylinder has a radius of 2 inches and a height of 2*12 + 5 - 7 = 22 inches, so its volume is:

V1 = pi * r^2 * h = pi * 2^2 * 22 = 276.46 in2

The cone has a radius of 2 inches and a height of 7 inches, so its volume is:

V2 = (1/3) * pi * r^2 * h = (1/3) * pi * 2^2 * 7 = 29.32 in2

Then, we have that the volume of the rocket is:

V = V1 + V2 = 276.46 + 29.32 = 305.78 in2

3 0

3 years ago