Team A has more spread out times, but they have the fastest times in their lower quartile.
Team B has more consistent times, but their times in the lower quartile are slower than Team A's. Their upper quartile times are faster than Team A's.
Both teams observed the same fastest and lowest times.
Both teams' medians are close to each other, but Team B has a slightly faster median.
The answer to that question will be A
Hi.
Your answer is going to be
B.) a9n0=3x3^(n-1)
Hope this helps! :)
Answer:
x=3
plug that in
123 is the answer
Step-by-step explanation:
Let the Number of Songs in the Music Player of Lou be : L
Given that Kelly has 4 times as many songs as Lou has in her Music Player
⇒ The Number of songs in Music Player of Kelly = 4 × L
Given that Tiffany has 6 times as many songs as Lou has in her Music Player
⇒ The Number of songs in Music Player of Tiffany = 6 × L
Given that Altogether have 682 songs in their Music Players
⇒ Tiffany songs + Lou songs + Kelly songs = 682
⇒ 6L + L + 4L = 682
⇒ 11L = 682
⇒ L = 62
⇒ Number of Songs in Music Player of Lou = 62
⇒ Number of Songs in Music Player of Kelly = 4 × L = 4 × 62 = 248